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allochka39001 [22]
2 years ago
13

A share of stock in the Lofty Cheese Company is quoted at 251/4. Suppose you hold 30 shares of that stock, which you bought at 2

01/4. If you sell your stock at 251/4, how much profit do you get or lose?
Mathematics
1 answer:
inn [45]2 years ago
3 0
You'll make a profit of $150.
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Every month your balance includes the original amount (100%) and the added the monthly interest  (1.42%)  so each  month  the balance will be 101.42%  of pior month's balance move  the decimal point two points two places to the left to make that into a decimal 

So the answer is 101.42
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2 years ago
Solve x2 + 10x + 12 = 36 for x.
tankabanditka [31]
X=2 my friend 
hope this helps!
8 0
2 years ago
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How do the graphs of the functions f(x) = (3/2)^x and g(x) = (2/3)^x compare?
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Sample Response: The graphs are reflections of each other over the y-axis. The graph of g(x) shoes exponential decay, while the graph of f(x) shows exponential growth.
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2 years ago
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Using two or more complete sentences, describe how to find the general rule for the arithmetic sequence with a4 = -1 and a6 = -1
adoni [48]

Answer:

Step-by-step explanation:

to find the arithmetic sequence with a4=-1 and a6=-13

first: find the difference: an=a+(n-1)d

a4=-1

that means a1+d(4-1)=-1 ( since a4 given and need to find a1)

a1+3d=-1 first equation

a1+d(6-1)=-13 ( a6 is given)

a1+5d=-13 second equation

a1+3d=-1

a1+5d=-13 ( find a and d by subtraction)

a1+3d-a1-5d=-1-(-13)

2d=12

d=-12/2=-6 ( substitute d in the equation: a1+3d=-1)

difference =-6

a1=17

a1,a2,a3,a4,a5,a6,....

the sequence is : 17,11,5,-1,-7,-13,.....

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5 0
2 years ago
Which is the equation of a parabola with vertex (0, 0), that opens to the left and has a focal width of 12?
sattari [20]

Answer:

\text{Equation of parabola is }y^2=-12x

Step-by-step explanation:

We need to find the equation of parabola using given information

  • Vertex: (0,0)
  • Open to the left
  • Focal width = 12

If parabola open left and passes through origin then equation is

y^2=-4ax

Focal width = 12

Focal width passes through focus and focus is mid point of focal width.

Focus of above parabola would be (-a,0)

Passing point on parabola (-a,6) and (-a,-6)

Now we put passing point into equation and solve for a

6^2=-4a(-a)

a=\pm 3

a can't be negative.

Therefore, a=3

Focus: (-3,0)

Equation of parabola:

y^2=-12x

Please see the attachment of parabola.

\text{Thus, Equation of parabola is }y^2=-12x

6 0
2 years ago
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