Answer:
Only Elijah's model is correct
Step-by-step explanation:
The data given in the question tells us they have 12 games left on their soccer team. Each one of them tried to simulate the fact by creating some model which look like a balance between quantities.
Elijah placed 3 cubes of value 1 and a cube of value x on one side of a balance. On the other side, he placed 15 cubes of value 1. He was obviously modeling the fact that 15 cubes (games due to play in our case) should be equal to 3 cubes (games already played) plus the x numbers left to play
This model if perfect, since the only way to equilibrate the balance is setting x to 12, the games left to play
Jonathan used a table with 3 x's in a row and a 15 in the second row, trying to model the same situation. To our interpretation, this table doesn't show the number of games left to play. If we equate 3x = 15, we get x=5 which has nothing to do with the situation explained in the question, so this model is not correct.
Answer:
He'll need 288 cups to make a waffle on his 24 foot diameter circular griddle.
Step-by-step explanation:
In order to find out how much batter Danny needs we first need to compute the area of the first pans, since it is a circular pan their area is given by A = 2*pi*r. So we have:
Area of the first pan = 2*pi*(6/2) = 18.84 square inches
Area of the second pan = 2*pi*(24/2) = 75.36 square foots
We now need to convert these values to be in the same unit, we'll convert from square foots to square inches:
Area of the second pan = 75.36 * (12)^2 = 10851.84 square inches
We can now use a proportion knowing that the batter and the thickness of the waffles are the same. If 0.5 cup of flour can make a waffle on 18.84 square inches then x cup of flour can make a waffle on 10851.85 square inches. Writing this in a mathematical form, we have:
0.5/x = 18.84/10851.84
18.84x = 0.5*10851.85
x = 10851.85*0.5/18.84 =288 cups
The conversion rate US dollars to Euros is represented with the function:
E(n)=0.72n
n- number of dollars
E(n) - Euros as a function of US dollars
The conversion rate Euros to Dirhams is :
D(x)=5.10x
x- number of Euros
D(x)- Dirhams as a function of Euros
<span>We are trying to find D(x) in terms of n.
D(x) = 5.10x
x can be rewritten as E(n)
D(x) = 5.10(E(n))
D(x) = 5.10(E(n))
D(x) = 5.10(0.72n)
D(x) = 3.672n </span>
According to this the following statement is true:
A) <span>(D x E)(n) = 5.10(0.72n)</span>
Answer: a.) 40320
b.) 336
Step-by-step explanation:
since we have 8 possible positions, with 8 different candidates, then there are 8 possible ways of arranging the first position, 7 possible ways of arranging the Second position, 6 ways of arranging the 3rd position, 5 possible ways od arranging the 4th position, 4 possible ways of arranging the 5th position, 3 possible ways of arranging the 6th position, 2 possible ways of arranging the 7th position and just one way of arranging the 8th position since we have only one person left.
Hence, the Number of possible sample space for different 8 positions is by multiplying all the number of ways we have in our sample space which becomes:
8*7*6*5*4*3*2*1 = 40320.
b.) By the sample space we have, since we've been asked ti arrange for only the firat 3 positions, then we multiply just for the first 3ways of choosing the positions, this becomes:
8*7*6 = 336
Answer:
The graph is shown below.
Step-by-step explanation:
Given:
The inequality of a line to graph is given as:
In order to graph it, we first make the 'inequality' sign to 'equal to' sign. This gives,
Now, we plot this line on a graph. The given line is of the form:
Where, 'm' is the slope and 'b' is the y-intercept.
So, for the line , 
The y-intercept is at (0, -3).
In order to draw the line correctly we find another point. Let the 'y' value be 0.
Now, 
So, the point is (3, 0).
Now, we mark these points and draw a line passing through these two points.
Now, consider the line inequality . The 'y' value is less than 
. So, the solution region will be region below the line and excluding all the points on the line. So, we draw a broken line and shade the region below it.
The graph is shown below.
