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Gelneren [198K]
2 years ago
11

Planes X and Y are perpendicular. Points A, E, F, and G are points only in plane X. Points R and S are points in both planes X a

nd Y. Lines EA and FG are parallel.
Planes X and Y are shown. Lines A E and F G are vertical and are on plane X. Line R S is at the intersection of the 2 planes.
Based on this information, which pair of lines, together, could be perpendicular to RS? Select two options.

Line E A
Line E R
Line E F
Line F G
Line F S
Mathematics
2 answers:
motikmotik2 years ago
9 0
Planes X and Y are perpendicular to each other
Points A, E, F, and G are points only in plane X
Points R and S are points in both planes X and Y
Lines EA and FG are parallel

The lines which could be perpendicular to RS are EA and FG.
RoseWind [281]2 years ago
8 0

Answer:

es, fg

Step-by-step explanation:

took test

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A jar of 150 jelly beans contains 22 red jelly beans, 38 yellow, 20 green, 28 purple, 26 blue, and the rest are orange.Let B = t
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Answer:

P(R\ and\ B) = 0.0256

Step-by-step explanation:

Given

Red = 22

Yellow = 38

Green = 20

Purple = 28

Blue = 26

Orange = 16

Required

Determine the probability of red then blue jelly? i.e. P(R and B)

From the question, we understand that the red jelly bean was not replaced. This means that the number of jelly beans reduced by 1 after the picking of the red jelly bean

So, we have:

P(R\ and\ B) = P(R)\ and\ P(B)

This is then solved further as:

P(R\ and\ B) = P(R)\ *\ P(B)

P(R\ and\ B) = \frac{n(R)}{Total}\ *\frac{n(B)}{Total - 1}

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The equation becomes:

P(R\ and\ B) = \frac{22}{150}\ *\frac{26}{150- 1}

P(R\ and\ B) = \frac{22}{150}\ *\frac{26}{149}

P(R\ and\ B) = \frac{22*26}{150*149}

P(R\ and\ B) = \frac{572}{22350}

P(R\ and\ B) = 0.02559284116

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The volume of the prism is 840 cubic units. What is the perimeter of the base?
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Same as what I explained in your last question.

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Hope this helps!!!


Thanks for using Brainly!
3 0
2 years ago
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