Answer:
34°
Step-by-step explanation:
If m∠ADE is with 34° smaller than m∠CAB, then denote
m∠ADE=x°,
m∠CAB=(x+34)°.
Since DE ║ AB, then
m∠ADE=m∠DAB=x°.
AD is angle A bisector, then
m∠EAD=m∠DAB=x°.
Thus,
m∠CAB=m∠CAD+m∠DAB=(x+x)°=2x°.
On the other hand,
m∠CAB=(x+34)°,
then
2x°=(x+34)°,
m∠ADE=x°=34°.
Answer:
t = 1.667 s
Step-by-step explanation
The distance traveled since the warning flag in feet is characterized by
d = 30*t^2 + 40*t
Where t is the time in seconds after the car starts accelerating.
We can easily solve this question by plotting the equation using a graphing calculator or plotting tool.
We need to find the time for which the distance d = 150 ft
150 = 30*t^2 + 40*t , t > =0
We can see that this value in the graph is approximately
t = 1.667 s
We can verify
30*(1.667)^2 + 40*(1.667 ) ≈ 150
A wall is in the shape of a trapezoid and it can be divided into a rectangle and a triangle. A triangle is with angles 45°- 45° - 90°. The hypotenuse of that triangle is 13√2 ft.Using the 45° - 45° - 90° theorem, sides of that triangle are in the proportion:x : x : x√2, and since that x√2 = 13√2 ( hypotenuse ), x = 13.Therefore h = 13 ft.We can check it: c² = 13² + 13²,c² = 169 + 169c² = 338c = √ 338 = 13√2Answer: h = 13 ft
Answer:
D) a chi square test for independence.
Step-by-step explanation:
Given that we suspect that automobile insurance premiums (in dollars) may be steadily decreasing with the driver's driving experience (in years), so we choose a random sample of drivers who have similar automobile insurance coverage and collect data about their ages and insurance premiums.
We are to check whether two variables insurance premiums and driving experience are associated.
Two categorical variables are compared for different ages and insurance premiums.
Hence a proper test would be
D) a chi square test for independence.
Time = distance/speed
The distance between the walkers increases at the rate of (8 mph) -(2 mph) = 6 mph. That distance will be 4.5 mi after ...
(4.5 mi)/(6 mi/h) = 4.5/6 h = 3/4 h
In 3/4 hour they will be 4.5 miles apart.