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Varvara68 [4.7K]

1 year ago

10

A small amphitheater has 8 rows that have 42 seats in each row. If an act needs to keep the first row empty but has all the rest

of the seats sold, then what expression can be used to find the total attendance? 8 × 40 + 8 × 2 8 × 40 – 8 × 2 7 × 40 + 7 × 2 7 × 40 – 7 × 2

1 answer:

jok3333 [9.3K]1 year ago

4 0

Answer:

i dont know sorry

Step-by-step explanation:

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Cameron, Arthur, and Jamie are playing soccer. Their locations are recorded by a motion tracking system. The grid shows distanc

Luden [163]

Answer:

1. Arthur is about 54 meters away from Cameron.

2. Jamie is about 56 meters away from Cameron.

3. Arthur is closer to Cameron.

Step-by-step explanation:

We have been given the locations of Cameron (70,10), Arthur (20,30) and Jamie (45,60) on the the grid in meters.

1. To find the distances of Arthur and Jamie from Cameron we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{(70-20)^{2}+(10-30)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{(50)^{2}+(-20)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{2500+400}$

$\text{Distance between Cameron and Arthur}=\sqrt{2900}$

$\text{Distance between Cameron and Arthur}=53.8516480713450403\approx 54$

Therefore, the distance Arthur is about 54 meters away from Cameron.

2. Let us find the distance between Cameron and Jamie.

$\text{Distance between Cameron and Jamie}=\sqrt{(70-45)^{2}+(10-60)^{2}}$

$\text{Distance between Cameron and Jamie}=\sqrt{(25)^{2}+(-50)^{2}}$

$\text{Distance between Cameron and Jamie}=\sqrt{625+2500}$

$\text{Distance between Cameron and Jamie}=\sqrt{3125}$

$\text{Distance between Cameron and Jamie}=55.9016994374947424\approx 56$

Therefore, Jamie is about 56 meters away from Cameron.

3. We can see that 56 is greater than 54, therefore, Arthur is closer to Cameron.

4 0

2 years ago

Read 2 more answers

The profitability, P, of a popular restaurant franchise can be modeled by the function P (t) = t4 – 10t3 + 28t2 – 24t, where t i

vekshin1

In this question, the profit of the restaurant after t months is given by a polynomial function. To find when it begins to show a profit, we find the numerical values of the function for t, and it shows a profit when $t > 0$

Profit after t months:

$P(t) = t^4 - 10t^3 + 28t^2 - 24t$

0 months:

This is P(0). So

$P(0) = 0^4 - 10*0^3 + 28*0^2 - 24*0 = 0$

1 month:

This is P(1). So

$P(1) = 1^4 - 10*1^3 + 28*1^2 - 24*1 = -5$

2 months:

This is P(2). So

$P(2) = 2^4 - 10*2^3 + 28*2^2 - 24*2 = 0$

3 months:

This is P(3). So

$P(3) = 3^4 - 10*3^3 + 28*3^2 - 24*3 = -9$

4 months:

This is P(4). So

$P(4) = 4^4 - 10*4^3 + 28*4^2 - 24*4 = -32$

5 months:

This is P(5). So

$P(5) = 5^4 - 10*5^3 + 28*5^2 - 24*5 = -45$

6 months:

This is P(6). So

$P(6) = 6^4 - 10*6^3 + 28*6^2 - 24*6 = 0$

7 months:

This is `P(7). So

$P(7) = 7^4 - 10*7^3 + 28*7^2 - 24*7 = 175$

After 7 months it shows profit, so it starts showing profit on the 6th month, and thus, the correct answer is given by option D.

For another example of a function involving numeric value, you can check brainly.com/question/24231879

8 0

1 year ago

Kx + 3x = 4 solve for x.

victus00 [196]

Take out a common factor between 3x and kx. That means use the distributive law to get what you normally would start with.

x(k + 3) = 4

Now divide by k + 3

x = 4/(k + 3)

That's as much as you can do with this question.

4 0

1 year ago

Jack,sally, and joe all work in a bookstore.jack sold 126 books.joe 1/2 as many books as jack,and sally sold 1/3 as many books a

Darina [25.2K]

Sally sold 2302323 books!

7 0

2 years ago

There are 53 students on the Jackson Middle School basketball teams. The number of 8th graders is 15 fewer than three times the

pshichka [43]

Answer:

The number of 7th students on the Jackson Middle School basketball teams is 17 and the number of 8th students on the Jackson Middle School basketball teams is 36

Step-by-step explanation:

Let

x ----> the number of 7th students on the Jackson Middle School basketball teams

y ----> the number of 8th students on the Jackson Middle School basketball teams

we know that

There are 53 students on the Jackson Middle School basketball teams

so

$x+y=53$ -----> equation A

The number of 8th graders is 15 fewer than three times the number of 7th graders

so

$y=3x-15$ ----> equation B

substitute equation B in equation A

$x+(3x-15)=53$

solve for x

$x+3x=53+15\\4x=68\\x=17$

Find the value of y

$y=3(17)-15=36$

therefore

The number of 7th students on the Jackson Middle School basketball teams is 17 and the number of 8th students on the Jackson Middle School basketball teams is 36

6 0

1 year ago

Read 2 more answers