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ANEK [815]
2 years ago
8

The cafeteria staff made sandwiches. Each sandwich had either rye or white bread, either ham or turkey, and either cheese or no

cheese. The staff made an equal number of each type of sandwich. The sandwiches were placed on a tray. Without looking, Mary will choose a sandwich. What are the chances that Mary will get a sandwich with cheese?1 eighth1 sixth1 third1 halfHide Toolbar
Mathematics
1 answer:
Anit [1.1K]2 years ago
8 0

Answer:

1/2 (1 half)

Step-by-step explanation:

The number of different sandwiches is calculated multiplying all of the possibilities for each material used:

rye or white bread: 2 options

ham or turkey: 2 options

cheese or no cheese: 2 options

So the number of different sandwiches that can be made is 2*2*2 = 8.

From these 8 different sandwiches, 4 have cheese and 4 have no cheese, as the staff made a equal number of each type of sandwich.

So, if from 8 different type of sandwiches, 4 have cheese, the chances of Mary getting a sandwich with cheese is 4/8 = 1/2 (1 half).

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One month julia collected 8.4 gallons of rainwater. That month she used 5.2 gallons of rainwater to water her garden and 6.5 gal
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Given

One month julia collected 8.4 gallons of rainwater.

she used 5.2 gallons of rainwater to water her garden

6.5 gallons of rainwater to water flowers

Find out how much was the supply of rainwater increased or decreased by the end of the month.

To proof

As given in the question

One month julia collected 8.4 gallons of rainwater

she used 5.2 gallons of rainwater to water her garden and 6.5 gallons of rainwater to water flowers

Total water she used in the month = 5.2 gallons + 6.5gallons

                                                         = 11.7 gallons

Let the supply of rainwater increased or decreased by the end of the month

be x .

Than the equation become in the form

x + 8.4 = 11.7

x = 3.3 gallons

Therefore the supply of rainwater increased or decreased by the end of the month is 3.3 gallons.

Hence proved



8 0
2 years ago
Read 2 more answers
A survey of 100 people in high school was used to find what subject was preferred. Fill in whats missing
asambeis [7]

Question: What's the joint frequency a 9th grader liked math?

<h3>Answer: 3%</h3>

Explanation:

Check out the attached image below. I've filled in the table with the missing values. The upper left corner is 3 because 7+3 = 10 in the first column. You'll fill in the other values in a similar fashion. Once we filled out the table, we can answer all of these questions. There are 3 ninth graders who like math out of 100 people total. So the final answer is 3/100 = 0.03 = 3%.

-----------------------------------

Question: What's the marginal relative frequency of 9th graders surveyed?

<h3>Answer: 10%</h3>

Explanation:

Again, refer to the table to find that there are 10 ninth graders out of 100 total. So 10/100 = 0.10 = 10% is the answer.

-----------------------------------

Question: Given a student was in 10th grade, what's the likelihood the student preferred English?

<h3>Answer:  46%</h3>

Explanation:

We only focus on the 10th graders because of the "given". There are 23 people in this row who like English out of 50 total sophomores. So 23/50 = 0.46 = 46% of the tenth graders liked English.

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Question: Given the subject was science, what's the likelihood the student was a freshman?

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Focus on the science column only. There are 29 freshmen out of 40 students total. We get the percentage of 29/40 = 0.725 = 72.5%

4 0
2 years ago
22. In the diagram below WXZ is a right angle. If the measure of WXV is 11 more than there times the measure of WXY and the meas
Andreyy89

Given: < WXZ = 90 degrees ( Right angle is an angle of 90 degree measure).

      m< WXV = 11 more than 3 times m< WXY = (3 * <WXY + 11)

      m< YXV = 139 degree.

To find : m<YXZ = ?

Solution : m< WXZ is equal to 90 degrees and is  also the sum of angles m<WXY and m<YXZ i.e.

          m< WXZ = 90 degrees = m<WXY + m<YXZ            -----(1)

           m< WXV = (3 * <WXY + 11)                       -----(2)

          m <YXV is equal to 139 degrees and also equal to the sum of angles m<WXY and m<WXV i.e.

          m <YXV = 139 degree = m<WXY + m<WXV            -----(3)

Substituting m< WXV = (3 * <WXY + 11) from equation (2) in equation (3)

         139 degree = m<WXY + m<WXV

      => 139 = m<WXY + 3 * m<WXY + 11  (Subtracting 11 from both sides)

      => 139 -11 =  m<WXY + 3 * m<WXY + 11 -11            

      => 128 = 4<WXY                                      (Adding m<WXY + 3 * m<WXY)

      => 32  = < WXY                                      (Dividing both sides by 4)

Substituting  < WXY = 32 from above in equation (1)

      90 degrees = m<WXY + m<YXZ

      90 = 32 + m<YXZ                                (Subtracting 32 from both sides)                                  

      90-32 = 32 + m<YXZ -32

      58 = m<YXZ.

Therefore, <YXZ =58 degrees.

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