Given data, cos(A - B) = cosAcosB + sinAsinB
<span>let, A=60' and B=30' ( here the ' sign bears degree) </span>
<span>L.H.S = cos(A - B) </span>
<span>=cos (60'-30) ( using value of A and B ) </span>
<span>=cos30' </span>
<span>= sqrt3/2 </span>
<span>R.H.S= cosAcosB + sinAsinB </span>
<span>=cos60' cos30' + sin60' sin30' </span>
<span>= 1/2* sqrt3/2+ sqrt3/2*1/2 </span>
<span>= sqrt3/4 + sqrt3/4 </span>
<span>=2 sqrt3/4 </span>
<span>= sqrt3/2 </span>
<span>so L.H.S =R.H.S or cos(A - B) = cosAcosB + sinAsinB</span>
Each angle has a sin, cos, and tan associated with it.
in a right angled triangle there are two other angles which each have ratios.
Answer:I can’t see the rest.
Step-by-step explanation:
Solve for x.
(3x+1)2-100=0
(3x+1)2=100
3x+1=100/2
3x=50-1
x=49/3
x=16.33333
Hope that helps. If you have any other questions feel free to ask me
Answer: 6 + n = 6n
Step-by-step explanation:
