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tigry1 [53]
2 years ago
10

a building security code has 2 numeric digits 0 through 9 followed by 2 letters. what is the probability that the first digit is

nine an last letter is A?​
Mathematics
2 answers:
sleet_krkn [62]2 years ago
7 0

If we remove human choices in creating the code the answer is 10 (the possible choices) times 26 (the possible choices) so 260 is the probability

svp [43]2 years ago
5 0

Answer: \dfrac{1}{260}

Step-by-step explanation:

Given : A building security code has 2 numeric digits 0 through 9 followed by 2 letters.

Total digits (0,1,2,3,4,5,6,7,8,9)= 10

Total letters in English Alphabet = 26

Then, the total number of ways to make a code if repetition is allowed :-

10\times10\times26\times26=67600

The number of ways to make a code with first digit is nine an last letter is A (we fix first position for 9 as 1 and the last position for a as 1) , if repetition is allowed :-

1\times10\times26\times1=260

Then, the probability that the first digit is nine an last letter is A :-

=\dfrac{260}{67600}=\dfrac{1}{260}

Hence, the probability that the first digit is nine an last letter is A= \dfrac{1}{260}

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Answer:

3rd option

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Step-by-step explanation:

So we are given the following points:

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This is a geometric sequence because there is a common ratio, 3. That is you can keep multiply 3 to a previous y-coordinate to get the next y-coordinate.

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So we have

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If you want to know the fifth term, just plug in 5:

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2 years ago
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marishachu [46]
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Source:
http://www.1728.org/kepler3a.htm



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The rest of the options are not factorable thus the zero product property won't apply to them.
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