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solmaris [256]
2 years ago
14

CORINA INDRAGESTE FOARTE MULT ANIMALELE IN DAR DE ZIU EI A PRIMIT O CARTE DESPRE LUMEA LOR MINUNATA IN PRIMA ZI EA A CITIT 36 DE

PAGINI IAR IN A DOUA ZI A TREIA ZI DIN REST CATE PAGIN MAI ARE DE CITIT STIIND CA ALBUMUL ARE IN TOTAL 159DE PAGINI?
Mathematics
1 answer:
aliya0001 [1]2 years ago
7 0
Paging that’s what I got for the answer
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Find the 88th term of the arithmetic sequence 26, 28, 30,...
ICE Princess25 [194]

Answer:

200

Step-by-step explanation:

Given Arithmetic sequence is: 26, 28, 30,...

First term a = 26

Common Difference d = 2

n = 88

\because t_n=a +(n-1) d \\  \therefore \: t_{88}=26 +(88-1)  \times 2 \\ \therefore \: t_{88}=26 +87  \times 2 \\ \therefore \: t_{88}=26 +174 \\ \huge \red{ \boxed{ \therefore \: t_{88}=200}} \\

4 0
2 years ago
Suppose that lower production costs increases the supply of wheat, such that more wheat is supplied at each price level. After t
just olya [345]

When the demand and supply curve intersect, that is, where the quantity demanded and quantity supplied are equal, the market is said to be in equilibrium. Thus, the given quantity is equilibrium quantity.

From the graph, we see that when the production cost of wheat is $4, the equilibrium quantity is 600 units.

When the production cost lowers from $4 to $3, the supply of wheat increases, such that the equilibrium quantity increases from 600 units to 800 units.

Thus, after an increase in supply, the equilibrium quantity increases.

So, Option A is the correct answer.

3 0
2 years ago
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Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components. From the shipment you take
MrRissso [65]

Answer:

mean (μ) = 4.25

Step-by-step explanation:

Let p = probability of a defective computer components = \frac{68}{400} = 0.17

let q = probability of a non-defective computer components = \frac{332}{400} = 0.83

Given random sample n = 25

we will find mean value in binomial distribution

The mean of binomial distribution = np

here 'n' is sample size and 'p' is defective components

mean (μ) = 25 X 0.17 = 4.25

<u>Conclusion</u>:-

mean (μ) =  4.25

6 0
2 years ago
Brant is preparing for the upcoming track season, and he wants to reduce the time of his 1-mile run. Last year, he conducted an
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The Q30X program and the Intensity program are both effective because the average participant 1-mile run time was reduced for each program, but the Intensity program is the more effective program because it yielded a greater decrease in the average participant 1-mile run time.

5 0
2 years ago
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Forty percent of the sheets of construction paper are secondary colors. There are 25 sheets of construction paper. How many of t
Alja [10]
10 of those sheets are secondary colors.

40% = 0.4
0.4(25) = 10
4 0
2 years ago
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