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SVETLANKA909090 [29]

2 years ago

12

Upper A 4-ft-tall fence runs parallel to the wall of a house at a distance of 8 ft. Find the length of the shortest ladder that

extends from the ground to the house without touching the fence. Assume the vertical wall of the house is 20 ft high and the horizontal ground extends 25 ft from the fence.

1 answer:

kherson [118]2 years ago

5 0

Answer:

Length of ladder = approximately 39 ft

Step-by-step explanation:

The formation is a right angle to and we are looking for the hypotenuse.

But first

The height = was of the house = 20ft

Total length = the 25ft extension+ the 8ft distance betwee the fence and the house

Total length= 25 +8 = 33ft

Length of the ladder = hypotenuse

Let length of the ladder be x

X² = 33² +20²

X² = 1089 + 400

X² = 1489

X= √1489

X= 38.59 ft

Length of ladder = approximately 39 ft

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Gnoma [55]

Answer:

The answer is 16 ÷ 2 = 8.

Step-by-step explanation:

Now, to find the expression modeled by arrangement of tiles.

So, according to the model in the question.

There are 16 tiles in the model.

So, arrangement of 16 tiles divided into 2 groups.

Where each group consist 8 tiles.

So, we can write as:

$16\div 2$

As 16 is the number of tiles and 2 is the number of groups.

Now, we can check the expression by doing the division.

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2 years ago

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Aramp is 17 feet long, rises 8 feet above the floor, and covers a horizontal distance of 15 feet, as shown in the figure.

bonufazy [111]

Answer:

The ratio of Tan B is

$\tan B= \dfrac{AC}{BC}=\dfrac{8}{15}$

OR

$\tan A= \dfrac{BC}{AC}=\dfrac{15}{8}$

Step-by-step explanation:

In Right Angle Triangle ABC

angle C = 90°

AB = Ramp = 17 feet

BC =Horizontal distance = 15 feet

AC = Height from floor = 8 feet

To Find:

Ratio of Tan B = ?

Solution:

In Right Angle Triangle ABC By Tangent Identity we have

$\tan B= \dfrac{\textrm{side opposite to angle B}}{\textrm{side adjacent to angle B}}$

Substituting the given values we get

$\tan B= \dfrac{AC}{BC}=\dfrac{8}{15}$

OR

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What is the answer to the problem 44.84 x 9.84?

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7 0

1 year ago

A function f(x) has x intercepts of -3 and -5. What is the constant term in the function?

Anon25 [30]

Answer:

The constant term in the function is 5

Step-by-step explanation:

we have

$f(x)=x^{2}+8x+b$

where

b is the y-intercept or the constant term of the function

Remember that

The x-intercept is the value of x when the value of the function is equal to zero

so

For x=-3 ----> f(x)=0

For x=-5 ----> f(x)=0

substitute any of the intercepts in the function

For x=-3

$0=(-3)^{2}+8(-3)+b$

$0=9-24+b$

$0=-15+b$

$b=15$

$f(x)=x^{2}+8x+15$

Verify with the other intercept

For x=-5

$0=(-5)^{2}+8(-5)+15$

$0=25-40+15$

$0=0$ ---> is true

therefore

The constant term in the function is 5

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2 years ago

A rectangular pool 18 meters by 12 meters is surrounded by a walkway of width x

vesna_86 [32]

Answer:

x=3 meters

Step-by-step explanation:

step 1

Find the area of the rectangular pool

$A=LW$

we have

$L=18\ m\\W=12\ m$

substitute

$A=18(12)=216\ m^2$

step 2

Find the area of rectangular pool including the area of the walkway

Let

x ----> the width of the walkway

we have

$L=(18+2x)\ m\\W=(12+2x)\ m$

substitute

$A=(18+2x)(12+2x)$

step 3

Find the area of the walkway

To find out the area of the walkway subtract the area of the pool from the area of rectangular pool including the area of the walkway

so

$A=(18+2x)(12+2x)-216$

step 4

Find the value of x if the area of the walkway equal the area of the pool

so

$(18+2x)(12+2x)-216=216$

Solve for x

$(18+2x)(12+2x)=432\\216+36x+24x+4x^{2}=432\\4x^{2} +60x-216=0$

Solve the quadratic equation by graphing

The solution is x=3 meters

see the attached figure

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