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omeli [17]
2 years ago
13

At the amusement park, Laura paid $6.00 for a small cotton candy. Her older brother works at the park, and he told

Mathematics
1 answer:
BabaBlast [244]2 years ago
8 0

Answer:

yes

The price of marked up candy is $6.00

perentage of mark up is 300%

let the marked up amount be represented as x

let 300% mark up be represented as 3x

the equatiopn for finding the price before markup

can be represented as 3x-x=$6.

                                    2x=$6

                                    x=$3.

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Yen paid $10.50 for 2.5 pounds of pretzels. What price did she pay for each pound of pretzels?
Furkat [3]

Answer:

The first step is to multiply by a power of 10, so the divisor is a whole number.

Step-by-step explanation:

8 0
2 years ago
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NEED HELP ASAP!!!!!
katen-ka-za [31]
If restaurant rotates 60^{0} every 15 minutes, then after one hour it will rotate 60^{0}*4=240^{0}.
When restaurant makes full rotation 360^{0}, the length will be 2 \pi r=2 \pi *80=160\pi. But 240^{0} <span>is only \frac{2}{3} from the full rotation, so the bird will pass 160\pi * \frac{2}{3} =335 ft
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</span><span>Answer: B is a correct choice
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8 0
2 years ago
A self-serve frozen yogurt store made these graphs to study the data collected about its customers' purchases. Which statement i
Diano4ka-milaya [45]

Answer:

strawberry yogurt makes up less than 1/3 of their sales

Step-by-step explanation:

In the first graph, the strawberry yogurt is a little larger than 1/4. Second, the yogurt increases instead of decreases n the first six months. And third, the store actually sold a little less than 3,000 yogurts in November than in August.

3 0
1 year ago
Henry bought 2 kilograms of chicken for a family dinner. After dinner, only 61.5 grams were left. How much chicken was eaten, in
DedPeter [7]

Answer:

1.99385kg of chicken was eaten.

Step-by-step explanation:

We first need to know how many grams were left in kilograms, so we can find the difference.

Unit conversion: 6.15g x 1kg/1000g = 0.00615kg

Eaten amount of chicken: 2kg - 0.00615kg = 1.99385kg

Hungry family, I suppose...

3 0
1 year ago
Which hyperbola has one focus point in common with the hyperbola (y+11)^2/(15^2)-(x-7)^2/(8^2)=1
irina [24]
\bf \textit{hyperbolas, vertical traverse axis }\\\\&#10;\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ({{ h}},{{ k}})\\&#10;vertices\ ({{ h}}, {{ k}}\pm a)&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y+11)^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\implies \cfrac{(y-(-11))^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\\\\&#10;-------------------------------\\\\&#10;c=\textit{distance from the center to either foci}\\\\&#10;c=\sqrt{a^2+b^2}\implies c=\sqrt{15^2+8^2}\implies \boxed{c=17}

now, if you notice, the positive fraction, is the one with the "y" variable, and that simply means, the hyperbola traverse axis is over the y-axis, so it more or less looks like the picture below.

now, from the hyperbola form, we can see the center is at (7, -11), and that the "c" distance is 17.

so, from -11 over the y-axis, we move Up and Down 17 units to get the foci, which will put them at (7, -11-17) or (7, -28) and (7 , -11+17) or (7, 6)

5 0
1 year ago
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