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kakasveta [241]
1 year ago
10

An elevator went up 15 floors, down 9 floors, up 11 floors and down 19 floors. Find the net change

Mathematics
2 answers:
mariarad [96]1 year ago
8 0

Answer:

The net change would be -2.

Step-by-step explanation:

The upward change of elevator is represented by positive sign while the downward change represented by negative sign.

Given,

First the elevator goes up 15 floors,

change = + 15,

Then it goes 9 floors down,

change = -9,

Then it goes 11 floors up,

Change = + 11,

Finally, it goes 19 floor down,

Change = - 19

So, the net change = sum of total changes = 15 - 9 + 11 - 19 = -2

Slav-nsk [51]1 year ago
3 0
15u + 11u - 9d - 19d = -2d
It went up 26, down 28, a net change of down 2.
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Exams are approaching and Helen is allocating time to studying for exams. She feels that with the appropriate amount of studying
svp [43]

Answer: 0.05

Step-by-step explanation:

Let M = Event of getting an A in Marketing class.

S = Event of getting an A in Spanish class,

i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45

Required probability = P(neither M nor S)

= P(M'∩S')

= P(M∪S)'                                 [∵P(A'∩B')=P(A∪B)']

=1- P(M∪S)                               [∵P(A')=1-P(A)]

= 1- (P(M)+P(S)- P(M∩S))   [∵P(A∪B)=P(A)+P(B)-P(A∩B)]

= 1- (0.80+0.60-0.45)

= 1- 0.95

= 0.05

hence, the probability that Helen does not get an A in either class= 0.05

3 0
2 years ago
Jenny is eight years older then twice her cousin sues age. The sum of their ages is less then 32. What is the greatest age that
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Answer:

The age of Sue could be 7 years

Step-by-step explanation:

Jenny is 8 years older than twice her cousin Sue's age.

The first equation will be :

J = 8 + 2S ---------(1)

The sum of their ages is less than 32.

The second equation will be :

J + S < 32  ----------------(2)

Now rearrange both equations :

8 + 2S + S < 32

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The age of Sue could be 7 years.

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1 year ago
Crossett Trucking Company claims that the mean weight of its delivery trucks when they are fully loaded is 6,000 pounds and the
solniwko [45]

Answer:

(5953.52,6046.49)

Step-by-step explanation:

We are given the following in the question:

Mean, \mu = 6,000 pounds

Sample size, n = 40

Alpha, α = 0.05

Standard deviation, σ = 150 pounds

95% Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

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are the limits within which 95% of the sample means occur.

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