You're looking for a value
such that
Because the distribution is symmetric, the value of
in either case will be the same.
Now, because the distribution is continuous, you have that
The mean for the standard normal distribution is
, and because the distribution is symmetric about its mean, it follows that
.
You can consult a
score table to find the corresponding score for this probability. It turns out to be
.
Hello,
Please, see the detailed solution in the attached files.
Thanks.
For the arithmetic sequence
a₁, a₂, a₃, ...,
the n-th term is
where d = the common difference
Because a₅ = 12.4,
a₁ + 4d = 12.4 (1)
Because a₉ = 22.4,
a₁ + 8d = 22.4 (2)
Subtract (1) from (2).
a₁ + 8d - (a₁ + 4d) = 22.4 - 12.4
4d = 10
d = 2.5
From (1),
a₁ = 12.4 - 4*2.5 = 2.4
Therefore
a₃₁ = 2.4 + 30*2.5 = 77.4
Answer: a₃₁ = 77.4
Answer:
One sample t-test for population mean would be the most appropriate method.
Step-by-step explanation:
Following is the data which botanist collected and can use:
- Sample mean
- Sample Standard Deviation
- Sample size (Which is 10)
- Distribution is normal
We have to find the best approach to construct the confidence interval for one-sample population mean. Two tests are used for constructing the confidence interval for one-sample population mean. These are:
- One-sample z test for population mean
- One-sample t test for population mean
One sample z test is used when the distribution is normal and the population standard deviation is known to us. One sample t test is used when the distribution is normal, population standard deviation is unknown and sample standard deviation is known.
Considering the data botanist collected, One-sample t test would be the most appropriate method as we have all the required data for this test. Using any other test will result in flawed intervals and hence flawed conclusions.
Therefore, One-sample t-test for population mean would be the most appropriate method.
