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zheka24 [161]
2 years ago
8

A square with sides of length eight units, sits on a graph with its lower left hand corner at the origin (0,0). This square is t

ranslated five units up, and seven units left. What are the coordinates of the ​upper right hand corner after translation? Explain.
PLEASE HELP ME ON THIS QUESTION. I don’t understand. Only answer if you know because you will receive consequences with monitor.

Mathematics
1 answer:
Masteriza [31]2 years ago
8 0

Answer:

The coordinates of the upper right hand corner after translation is (1, 13)

Step-by-step explanation:

<em>Let us revise the rules of translation</em>

  • If the point (x , y) translated horizontally to the right by h units then its image is (x + h , y) ⇒ T (x , y) → (x + h , y)
  • If the point (x , y) translated horizontally to the left by h units then its image is (x - h , y) ⇒ T (x , y) → (x - h , y)
  • If the point (x , y) translated vertically up by k units then its image is (x , y + k)→ (x + h , y) ⇒ T (x , y) → (x , y + k)
  • If the point (x , y) translated vertically down by k units then its image is (x , y - k) ⇒ T (x , y) → (x , y - k)

<em>At first let us find the upper right hand corner of the square</em>

∵ Its lower left hand corner at the origin (0,0)

∵ The length of each side of the square is 8 units

→ To find lower right hand corner add 8 to the x-coordinate of the

   lower left hand corner

∴ The lower right hand corner = (0 + 8, 0)

∴ The lower right hand corner = (8, 0)

→ To find upper right hand corner add 8 to the y-coordinate of the

   lower right hand corner

∴ The upper right hand corner = (8, 0 + 8)

∴ The upper right hand corner = (8, 8)

<em>Now Let us find the image of this corner after translation</em>

∵ This square is translated five units up

→ Use the 3rd rule above

∴ Add 5 to the y-coordinate of the point (8, 8)

∴ Its image = (8, 8 + 5)

∴ Its image = (8, 13)

∵ The square is translated seven units left

→ Use the 2nd rule above

∴ Subtract 7 from the x-coordinate of the point (8, 13)

∴ Its image = (8 - 7, 13)

∴ Its image = (1, 13)

The coordinates of the upper right hand corner after translation is (1, 13)

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Answer:

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The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. πa² ≥ k/∝

Step-by-step explanation:

a.

The rate of volume of water in the pond is calculated by

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Given

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The surface of the pond and that's where evaporation occurs.

The area of a circle is πr² with ∝ as the coefficient of evaporation.

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The volume of the conical pond is calculated by πr²L/3

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Substitute ∛(3aV/πh) for r in equation 1

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dV/dt = k - ∝π((3aV/πh)^⅓)²

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dV/dt = K - ∝π(3a/πh)^⅔V^⅔

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The equilibrium depth of water is when the differential equation is 0

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V = (k^3/2)/[(∝π.π^-⅔(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝π^⅓(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝^3/2.π^½.(3a/h))]

V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

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k - ∝πa² ≤ 0 ---- subtract k from both w

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A taut string of length 10 inches is plucked at the center. The vibration travels along the string at a constant rate of c inche
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Answer:

The correct option is

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Step-by-step explanation:

The parameters given are;

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The position on the string from the left-most end = x

The time duration of motion of the vibration to reach x= 0.3 milliseconds

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On the right side of the center, the distance from x is -(5 - x) = x - 5

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