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vlada-n [284]
2 years ago
7

For which of the following counts would a binomial probability model be reasonable? a. The number of traffic tickets written by

each police officer in a large city during one month. b. The number of hearts in a hand of five cards dealt from a standard deck of 52 cards that has been thoroughly shuffled. c. The number of 7's in a randomly selected set of five random digits from a table of random digits. d. The number of phone calls received in a one-hour period. e. All of the above.
Mathematics
1 answer:
timama [110]2 years ago
5 0

Answer:

c. The number of 7's in a randomly selected set of five random digits from a table of random digits.

True, for this case we have a value fixed for n =5 and the probability is defined for each number 1/10 assuming numbers (0,1,2,3,4,5,6,7,8,9) so then the random variable "The number of 7's in a randomly selected set of five random digits" can be modelled with the binomial probability function.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n, p)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

The conditions to apply this distribution is that we have the parameters fixed n and p.

Let's analyze one by one the possible solutions:

a. The number of traffic tickets written by each police officer in a large city during one month.

False, the number of traffic tickets written by each police is not a fixed amount always, so then the value of n change and we can't apply a binomial model for this case.

b. The number of hearts in a hand of five cards dealt from a standard deck of 52 cards that has been thoroughly shuffled.

False, not all the hands of size 5 are equal and since we can't ensure this condition then the binomial model not apply for this case

c. The number of 7's in a randomly selected set of five random digits from a table of random digits.

True, for this case we have a value fixed for n =5 and the probability is defined for each number 1/10 so then the random variable "The number of 7's in a randomly selected set of five random digits" can be modelled with the binomial probability function.

d. The number of phone calls received in a one-hour period.

False, the number of phone calls change by the hour and is not always fixed so then we don't have a valu for n, and the binomial model not applies for this case.

e. All of the above.

False option C is correct.

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Korolek [52]

Answer:

The input value that produces the same output value in both charts is 2.

Step-by-step explanation:

You are given two functions f(x)=-0.5x+2 and g(x)=2x-3 with tables

\begin{array}{cc}x&f(x)\\-3&3.5\\-2&3\\-1&2.5\\0&2\\1&1.5\\2&1\\3&0.5\end{array}

and

\begin{array}{cc}x&g(x)\\-3&\\-2&\\-1&\\0&\\1&\\2&\\3&\end{array}

First, fill in the second table:

g(-3)=2\cdot (-3)-3=-6-3=-9\\ \\g(-2)=2\cdot (-2)-3=-7\\ \\g(-1)=2\cdot (-1)-3=-5\\ \\g(0)=2\cdot 0-3=-3\\ \\g(1)=2\cdot 1-3=-1\\ \\g(2)=2\cdot 2-3=1\\ \\g(3)=2\cdot 3-3=3

Hence, the second table is

\begin{array}{cc}x&g(x)\\-3&-9\\-2&-7\\-1&-5\\0&-3\\1&-1\\2&1\\3&3\end{array}

The input value that produces the same output value in both charts is 2.

6 0
2 years ago
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What logarithmic function represents the data in the table?
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x = 6^f(x)
log x = log 6^f(x) = f(x)log 6
f(x) = log x / log 6 = log_6x
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Select the graph of the solution. Click until the correct graph appears.<br><br> |x| + 3 &gt; 7
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Answer:

Graph 3.

Step-by-step explanation:

|x| + 3 > 7

|x| > 4

This means x > 4 or x < -4,

which is the third graph.

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2 years ago
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For positive acute angles
insens350 [35]

9514 1404 393

Answer:

  77/85

Step-by-step explanation:

<u>Given</u>:

  cos(A) = 4/5

  sin(B) = 15/17

<u>Find</u>:

  cos(A-B)

<u>Solution</u>:

From your knowledge of Pythagorean triples, you know that one of them is (3, 4, 5) and another is (8, 15, 17). Using your imagination, or by drawing the triangles, you can determine the needed trig functions to be ...

  sin(A) = 3/5

  cos(B) = 8/17

__

Alternatively, you can use the Pythagorean identity to find ...

  sin(A) = √(1 -cos²(A)) = √(1 -(4/5)²) = √(9/25) = 3/5

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__

Then application of the angle difference formula is straightforward.

  cos(A -B) = cos(A)cos(B) +sin(A)sin(B)

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_____

Some graphing calculators can express the result ...

  cos(arccos(4/5) -arcsin(15/17)) ≈ 0.90588235294

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Paul [167]

Answer:

Refer to explanation

Step-by-step explanation:

Flour:

1 1/4 cups = 5/4 cups

5/4 ÷ 4 = 5/4 × 1/4

= 5/16 cups flour per serving

Sugar (Brown):

1/3 cup ÷ 4 = 1/3 × 1/4

=1/12 cups brown per serving

Sugar (white):

3/4 ÷ 4 = 3/16 cups per serving

For 6 servings:

Flour: 5/16 × 6 = 1 7/8 cups

Sugar (B): 1/12 × 6 = 1/2 cup

Sugar (W): 3/16 × 6 = 1 1/8 cups

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