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kondaur [170]
2 years ago
12

Tony’s class needs more than $500 for the school dance. So far, they have raised $200. They plan to have a car wash, charging $8

a car, to raise more money. Tony solved the inequality 8x + 200 Greater-than-or-equal-to 500, and determined that if they wash 37 cars, they will have enough money. Is he correct
Mathematics
2 answers:
adell [148]2 years ago
5 0

Answer:

38

Step-by-step explanation:

The solution to the inequality is x Greater-than-or-equal-to 37.5.

For this situation, only whole number solutions make sense.

Tony needs to round up to 38.

Orlov [11]2 years ago
4 0

Answer: no Tony is not correct It is less than 5 hundred dollars.

Step-by-step explanation: 8×37=296 +200 = 496

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jeka94
The width is half the length, so is
  width = (1/2)*length
  width = (1/2)*(<span>3.2a + 0.18b) cm
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  perimeter = 2*(length + width)
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Sasha did not get this answer, so apparently ...
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8 0
2 years ago
A really bad carton of eggs contains spoiled eggs. An unsuspecting chef picks eggs at random for his ""Mega-Omelet Surprise."" F
Dima020 [189]

Answer:

(a) The probability that of the 5 eggs selected exactly 5 are unspoiled is 0.0531.

(b) The probability that of the 5 eggs selected 2 or less are unspoiled is 0.3959.

(c) The probability that of the 5 eggs selected more than 1 are unspoiled is 0.8747.

Step-by-step explanation:

The complete question is:

A really bad carton of 18 eggs contains 8 spoiled eggs. An unsuspecting chef picks 5 eggs at random for his “Mega-Omelet Surprise.” Find the probability that the number of unspoiled eggs among the 5 selected is

(a) exactly 5

(b) 2 or fewer

(c) more than 1.

Let <em>X</em> = number of unspoiled eggs in the bad carton of eggs.

Of the 18 eggs in the bad carton of eggs, 8 were spoiled eggs.

The probability of selecting an unspoiled egg is:

P(X)=p=\frac{10}{18}=0.556

A randomly selected egg is unspoiled or not is independent of the others.

It is provided that a chef picks 5 eggs at random.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.556.

The success is defined as the selection of an unspoiled egg.

The probability mass function of <em>X</em> is given by:

P(X=x)={5\choose x}(0.556)^{x}(1-0.556)^{5-x};\ x=0,1,2,3...

(a)

Compute the probability that of the 5 eggs selected exactly 5 are unspoiled as follows:

P(X=5)={5\choose 5}(0.556)^{5}(1-0.556)^{5-5}\\=1\times 0.05313\times 1\\=0.0531

Thus, the probability that of the 5 eggs selected exactly 5 are unspoiled is 0.0531.

(b)

Compute the probability that of the 5 eggs selected 2 or less are unspoiled as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

              =\sum\imits^{2}_{x=0}{{5\choose 5}(0.556)^{5}(1-0.556)^{5-5}}\\=0.0173+0.1080+0.2706\\=0.3959

Thus, the probability that of the 5 eggs selected 2 or less are unspoiled is 0.3959.

(c)

Compute the probability that of the 5 eggs selected more than 1 are unspoiled as follows:

P (X > 1) = 1 - P (X ≤ 1)

              = 1 - P (X = 0) - P (X = 1)

              =1-\sum\limits^{1}_{x=0}{{5\choose 5}(0.556)^{5}(1-0.556)^{5-5}}\\=1-0.0173-0.1080\\=0.8747

Thus, the probability that of the 5 eggs selected more than 1 are unspoiled is 0.8747.

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Alex Ar [27]

Answer:

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Answer:

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Step-by-step explanation:

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We have to solve the equation to find the value of n.

Solving the equation, we get,

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Thus, value of n is 1.

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2 years ago
The ruby- throated hummingbird has a wing beat of about 200 beats per second. About how many wings beats would a huming bird hav
marishachu [46]
Well 200 beats per second is 12,000 beats a minute times 3 for 3 minutes is 36,000 beats every three minutes

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2 years ago
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