Let
x-------> the cost of the burger
y-------> the cost of the <span>sandwiches
we know that
3x+2y=27-----> equation 1
2x+y=27-11-----> 2x+y=16-----> multiply by -2-----> -4x-2y=-32--> equation 2
adds equation 1 and equation 2
</span> 3x+2y=27
-4x-2y=-32
<span>----------------
-x=27-32-----> x=5
3*5+2y=27----> 2y=27-15-----> y=6
therefore
the answer is the option
</span><span>3) The student's conclusion is correct because the solution to the system of equations 3x + 2y = 27 and 2x + y = 16 is (5, 6).</span>
You didn't say if the car bought is the new car or the old car so I'm assuming the car bought for $22,500 is the new car.
You divide 22,500 by 2 to get the cost of the old car. When you do this, you find out the old car costed $11,250.
the equation is 22,500/2=p
If $22,500 is the cost of the old car, then it's not my fault that the poster did not make it clear. If the previous car costed $22,500, then the previous car costed $22,500
To apply the changes to the equation of a vertical stretch of 4 and a translation of 3 units to the right, as well as the correct answer would be choice B.
The reason for this is when you apply a vertical stretch, because it changes the y-values (which causes it to vertically stretch or appear skinnier when graphed), you would multiply 4 to f(x) which would look like 4x^2.
Then, since you have a reflection over the x-axis, you must multiply a -1 to f(x) to reflect it over the x-axis which would result in -4x^2.
Finally, it also asks to shift the graph right 3 which by moving it right, you change the x values meaning you will perform f(x-3) to achieve this (subtract the value from x when you move right, and add the value to x when you move left).
This therefore results in your answer, the new graph would be
g(x)= -4(x-3)^2 or choice B.
