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Andru [333]
1 year ago
5

Which point can be used to create a right triangle that has ab as it’s hypotenuse?

Mathematics
2 answers:
Finger [1]1 year ago
4 0

Answer:

The point that can be used to create a right triangle that has AB as it’s hypotenuse is (3,3)

Step-by-step explanation:

From the attached diagram, the point to create a right triangle will be traced to the and y axis.

Let the point be represented with C(x,y)

At point A, tracing the line to x axis gives 3 x = 3

At point B, tracing the line to y axis gives also 3. y = 3

C(x,y) = C(3,3)

Hence, the point that can be used to create a right triangle that has AB as it’s hypotenuse is (3,3)

TEA [102]1 year ago
3 0
The answer is C (-3,3) because in each answers provided the x value should be read first

Hope this helps ☺
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Davis has 141 figures in his action figure collection. One-third of the figures are sports related. How many of the figures in D
Lelu [443]

We have been given that Davis has 141 figures in his action figure collection. One-third of the figures are sports related.

To find the number of figures that are not sports related we will find 2/3 of 141 as 2/3 of the figures will be not related to sports.

\text{ Figures not related to sports}=141\times\frac{2}{3}

\text{ Figures not related to sports}=47\times2

\text{ Figures not related to sports}=94

Therefore, 94 figures in Davis’ collection are not sports related.

 

7 0
1 year ago
Which is greater 3.6 m or 36 cm?
WARRIOR [948]

Answer:

36

Step-by-step explanation:

36 is greater than 3.6

7 0
2 years ago
Read 2 more answers
The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
grigory [225]

Answer:

142.2 meters.  

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

Let us find total surface area of box using surface area formula of cuboid.

\text{Total surface area of cuboid}=2(lb+bh+hl), where,

l = Length of cuboid,

b = Breadth of cuboid,

w = Width of cuboid.

\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

\text{Total surface area of box}=2(2520+432+840)

\text{Total surface area of box}=2(3792)

\text{Total surface area of box}=7584

Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0
2 years ago
A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s
denpristay [2]

Answer:

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=40-1=39

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

3 0
2 years ago
Henry and walter open savings accounts at the same time. henry invests $6,500 at 4.54% simple interest, and walter invests $7,10
MatroZZZ [7]
$331.52 is the correct answer
7 0
1 year ago
Read 2 more answers
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