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hjlf
2 years ago
15

If QRS TUV, which congruences are true by CPCTC? Check all that apply.

Mathematics
2 answers:
Morgarella [4.7K]2 years ago
4 0

It is given thatΔ QRS ≅Δ TUV

Out of all the given options

(C) QS= TV [C P C T}

(D) QR =TU

(E) S = V

(F) R= U

C, D,E, F are correct options.

Because when two triangles are congruent their corresponding parts are equal.

CPCT means corresponding parts of congruent triangles.

All these options are congruent by CPCT.

Side QR is congruent to TU.

Side Q S  is congruent to TV.

Angle S is Congruent to Angle V.

Angle R is congruent to Angle U.

The meaning of congruency of shapes is that the two or many more shapes are identical.


mr Goodwill [35]2 years ago
3 0

Answer:

Side QR is congruent to TU.

Side Q S  is congruent to TV.

Angle S is Congruent to Angle V.

Angle R is congruent to Angle U.

Step-by-step explanation:

i took the test

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a) n(none) = 25

b) n(PE but not Bio) = 25

c) n(ENG but not both BIO and PE) = 55

d) n(students that did not take Eng or Bio) = 40

e) P( Students did not take exactly two subjects) = 0.65

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From the Venn diagram drawn:

a) Number of students that took none

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n(all three) = 5

n (PE and Bio) = 10

n(PE and Eng) = 15

n(Bio and Eng) = 7

n (PE and Bio only) = 10 - 5 = 5

n(PE and Eng only) = 15 - 5 = 10

n(Bio and Eng only) = 7 - 5 = 2

n(PE only) = 35 - 5 - 5 - 10 = 15

n(Bio only) = 42 - 5 - 5 - 2 = 30

n(Eng only) = 60 - 10 - 5 -2 = 43

n(Freshmen) = n(PE only) + n(Bio only) + n(Eng only) + n(PE and Bio only) + n(PE and Eng only) + n(Bio and Eng only) + n(all three) + n(none)

135 = 15 + 30 + 43 + 5 + 10 + 2 + 5 + n(none)

135 = 110 + n(none)

n(none) = 135 - 110

n(none) = 25

b)Number of students that too PE but not Bio

n(PE but not bio)= n(PE only) + n(PE and Eng only)

n(PE but not Bio) = 15 + 10

n(PE but not Bio) = 25

c) Number of students that took ENG but not both BIO and PE

n(ENG but not both BIO and PE) = n(Eng only) + n(Eng and Bio only) + n(Eng and PE only) = 43 + 2 + 10

n(ENG but not both BIO and PE) = 55

d) Number of students that did not take ENG or BIO

n( students that did not take Eng or Bio) = n(PE only) + n(none)

n(students that did not take Eng or Bio) = 15 + 25

n(students that did not take Eng or Bio) = 40

e) Probability that a randomly-chosen student from this group did not take exactly two subjects

n( Students that did not take exactly two subjects) = n(PE only) + n(Bio only) + n(Eng only)

n( Students that did not take exactly two subjects) = 15 + 30 + 43

n( Students that did not take exactly two subjects) = 88

P( Students did not take exactly two subjects) = 88/135

P( Students did not take exactly two subjects) = 0.65

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