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NeX [460]
2 years ago
7

The range of the function given below is the set of all positive real numbers greater than 6. F(x)=6+2^x

Mathematics
1 answer:
rewona [7]2 years ago
6 0
That's right. what's the problem?
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\bf (x)(x+2)=255\implies x^2+2x=255\implies x^2+2x-255=y
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\textit{setting y=0}\implies x^2+2x-255=0
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\textit{now, factoring that}
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(x+17)(x-15)=0\implies 
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notice the picture of the graph added here
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the graph is touching the x-axis, an x-intercept
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2 years ago
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so the final result will 104.
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