If y ∝ 1∕x and y = –2 when x = 14, find the equation that connects x and y.
1 answer:
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So, we would need to remember, the one way that me personally would view square rooting would be by simplifying them, and that number would go into that number that many times. So, when doing this kind of problem, we are not truly going to do this, but we are just going to simplify it, and to see what other square "rooter" would go into that.
So, we would need to remember a (key) point, <em>we aren't just multiplying, for the most part, we're simplifying. </em>
Our result:
![\boxed{\boxed{\bf{2a^2b \sqrt[4]{24a^2b^3} }}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Cbf%7B2a%5E2b%20%5Csqrt%5B4%5D%7B24a%5E2b%5E3%7D%20%7D%7D%7D)
We didn't just multiplied it, we also simplified it also.
So, we would need to remember a (key) point, <em>we aren't just multiplying, for the most part, we're simplifying. </em>
Our result:
We didn't just multiplied it, we also simplified it also.
M is mid point of CP. M will divide the BPC in two equal parts
BMC and
BMP.
Area of BMP is equal to 21m^2
Since, BMC =
BMP
Area of BPC = Area of
BMC +Area of
BMP = 21 + 21 = 42m^2
and since ratio of AP:BP =1:3 so the area of BMP will be 1/3 of Area of
ABC
hence, Area of ABC = 63m^2
