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Lady_Fox [76]
1 year ago
6

If y ∝ 1∕x and y = –2 when x = 14, find the equation that connects x and y.

Mathematics
1 answer:
crimeas [40]1 year ago
8 0

C. y= -28/x

y=k/x

cross multiply

k= y×x

k = -2×14

k = -28

y = -28/x [ equation connecting x and y]

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For a few months, Dexter recorded the amounts, in fluid ounces, of laundry detergent remaining y after he and his family washed
BigorU [14]
Definitely it's B:  The amt of detergent left after x loads have been washed is y = (-$1.60/load)x + 50.
3 0
1 year ago
Find a matrix P such that PTAP orthogonally diagonalizes A. Verify that PTAP gives the proper diagonal form. (Enter each matrix
krok68 [10]

Answer:

the P matrix you are looking for is P=(1/\sqrt{2}) · [[1 1 0 0],[1 -1 0 0],[0 0 1 1],[0 0 1 -1]]

Step-by-step explanation:

Answer:

For an orthogonal diagonalization of any matrix you have to:

1º) Find the matrix eigenvalues in a set order.

2º) Find the eigenvectors of each respective eigenvalues.

Tip: You can write the matrix A like A = P^{t} D P

3º) D is the diagonal matrix with each eigenvalue (in order) in the diagonal.

4º) Write P as the normalized eigenvectors in order (in columns).

Tip 2: Remember, P^{t}·P = I, so if A = P^{t} D P, then:

P A P^{t} = P  P^{t} D P P^{t} = I D I = D

So the P we are looking for is the P^{t} of the diagonalization.

Tip 3: In this case, A is a block matrix with null nondiagonal submatrixes, therefore its eigenvalues can be calculated by using the diagonal submatrixes. The problem is reduced to calculate the eigenvalues of A₁₁ = A ₂₂ = [[5 3],[3 5]]

Solving:

1º)the eigenvalues of A₁₁ are {8,2}, therefore the D matrix is \left[\begin{array}{cccc}8&0&0&0\\0&2&0&0\\0&0&8&0\\0&0&0&2\end{array}\right]

2º) the eigenvectors of A₁₁ are P₈= {[1 1]T} P₂= {[1 -1]T}, therefore normalizing the eigenvectors you obtain P = (1/\sqrt{2}) · [[1 1 0 0],[1 -1 0 0],[0 0 1 1],[0 0 1 -1]] (you can see that P =  P^{t} in this case).

As said in "tip 2": P A P^{t} = P  P^{t} D P P^{t} = I D I = D

So the P obtained is the one you are looking for.

4 0
2 years ago
For questions 2-5, the number of pieces in a regular bag of Skittles is approximately normally distributed with a mean of 38.4 a
aleksley [76]

Answer:

a. -1.60377

b. 0.25451

c. 0.344

d. Option b) 78th

Step-by-step explanation:

The number of pieces in a regular bag of Skittles is approximately normally distributed with a mean of 38.4 and a standard deviation of 2.12.

a)What is the z-score value of a randomly selected bag of Skittles that has 35 Skittles? a) 1.62 b) -1.62 c) 3.40 d) -3.40 e)1.303.

The formula for calculating a z-score is is z = (x-μ)/σ,

where x is the raw score

μ is the population mean

σ is the population standard deviation.

z = 35 - 38.4/2.12

= -1.60377

Option b) -1.62 is correct

b) What is the probability that a randomly selected bag of Skittles has at least 37 Skittles? a) .152 b) .247 c) .253 d).747e).7534. .

z = (x-μ)/σ

Mean of 38.4 and a standard deviation of 2.12.

z = (37 - 38.4)/2.12

= -0.66038

P-value from Z-Table:

P(x<37) = 0.25451

The probability that a randomly selected bag of Skittles has at least 37 Skittles is 0.25451

Option c) .253 is.correct

c) What is the probability that a randomly selected bag of Skittles has between 39 and 42 Skittles? a) .112 b) .232 c) .344 d).457 e).6125.

z = (x-μ)/σ

Mean of 38.4 and a standard deviation of 2.12.

For 39 Skittles

z = (39 - 38.4)/2.12

= 0.28302

Probability value from Z-Table:

P(x = 39) = 0.61142

For 42 Skittles

z = (42 - 38.4)/2.12

= 1.69811

Probability value from Z-Table:

P(x = 42) = 0.95526

The probability that a randomly selected bag of Skittles has between 39 and 42 Skittles is:

P(x = 42) - P(x = 39

0.95526 - 0.61142

0.34384

= 0.344

Option c is.correct

d) What is the percentile rank of a randomly selected bag of Skittles that has 40 Skittles in it? a)82nd b) 78th c) 75th d)25th e)22nd

z = (x-μ)/σ

Mean of 38.4 and a standard deviation of 2.12.

z = (40 - 38.4)/2.12

= 0.75472

P-value from Z-Table:

P(x = 40) = 0.77479

Converting to percentage = 0.77479× 100

= 77. 479%

≈ 77.5

Percentile rank = 78th

7 0
2 years ago
Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc
babunello [35]

For this case, the first thing we are going to do is write the generic equation of motion for the vertical axis.

We have then:

h = \frac {1} {2} gt ^ 2 + vo * t + h0

Where,

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  • <em>vo: initial speed </em>
  • <em>h0: initial height </em>

For the first body:

h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21

For the second body:

h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

By the time both bodies have the same height we have:

h1 = h2\\

\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

Rewriting we have:

\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50

\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21

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Clearing time:

t = 29 (\frac {12} {19})\\t = 18.31s

Answer:

 it takes 18.31s for the two window washers to reach the same height

6 0
2 years ago
Read 2 more answers
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Tcecarenko [31]

Answer:

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Step-by-step explanation:

<h3>Answer options:</h3>

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<u>B. a higher principal. </u>

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<u>D. a higher number of payments.</u>

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