Notice that form 3 pm to 6:30 pm 3.5 hours have passed.
Since the function
represent the average number of cars that pass through an intersection x hours after 3:00 p.m, we are going to replace
with 3.5 to find <span>the average number of cars that pass through the intersection at 6:30 p.m
</span>
We can conclude that the <span>average number of cars that pass through an intersection at 6:30 pm is approximately 117. </span>
Answer:
<em>after 4seconds</em>
Step-by-step explanation:
Given the height, h , in feet, of the football above the ground after t seconds expressed by h ( t ) = − 8 t^2 + 32 t, the height of the ball on the ground is 0feet.
Substitute h(t) = 0 into the expression and calculate t;
h ( t ) = − 8 t^2 + 32 t
0 = − 8 t^2 + 32 t
8t² = 32t
8t = 32
Divide both sides by 8
8t/8 = 32/8
<em>t = 4s</em>
<em>Hence the football hits the ground after 4seconds</em>
Answer:
If s(x) = x – 7 and t(x) = 4x2 – x + 3, which expression is equivalent to (t*s)(x)? 4(x – 7)2 – x – 7 + 3 4(x – 7)2 – (x – 7) + 3 (4x2 – x + 3) – 7 (4x2 – x + 3)(x – 7)
Hi there! I can help you! Okay. So to find the amount of interest, we have to do the formula prt. That means multiply the principal, which is the initial amount of money, the rate, which is the interest rate, and the amount of time, which is usually in years. With that being said, here is how the answers turn out.
$252, 8% for 2 years: $40.32
$400, 2% for 6 months: $4
$5,000, 3.5% for 1 year: $175
$6,240, 10% for 9 months: $468
For the months, we just convert those numbers into decimal. 6 months is 1/2 a year, so it would be 0.5 and 9 months is 3/4 of a year, so that decimal would be 0.75. All you have to do is multiply the amount of money by percentage (you can do it by decimal form) by amount of time, and you’ll be good.
Answer:
The function is ![f(x) = 4(\sqrt[3]{16} )^{2x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%204%28%5Csqrt%5B3%5D%7B16%7D%20%29%5E%7B2x%7D)
.
Step-by-step explanation:
We have to choose from options the exponential function which has a simplified base of 4∛4 i.e. ∛(256).
Now, the exponential function in the option III will be the answer.
The function is .
So, the base is ![(\sqrt[3]{16} )^{2}](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B16%7D%20%29%5E%7B2%7D)
= ![\sqrt[3]{16^{2}} = \sqrt[3]{256} = 4\sqrt[3]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B16%5E%7B2%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B256%7D%20%3D%204%5Csqrt%5B3%5D%7B4%7D)
. (Answer)
The general formula of an exponential function is 
, where b is called the base of the function.
