Answer:
The dimensions that minimize the amount of cardboard used is
x = 31 cm , y = 34 cm & Z = 15.54 cm
Step-by-step explanation:
Volume of the cardboard = 16,384 
The function that represents the area of the cardboard without a lid is given by
------ (1)
Volume of the cardboard with sides x, y & z is
Put this value of z in equation (1) we get
Differentiate above equation with respect to x & y we get
Take 
------ (2)
------- (3)
By solving equation (2) & (3) we get
x = 31 cm
From equation 2
y = 32768 (
)
y = 34 cm
Z = 15.54 cm
Thus the dimensions that minimize the amount of cardboard used is
x = 31 cm , y = 34 cm & Z = 15.54 cm
Answer:
The variance in weight is statistically the same among Javier's and Linda's rats
The null hypothesis will be accepted because the P-value (0.53 ) > ∝ ( level of significance )
Step-by-step explanation:
considering the null hypothesis that there is no difference between the weights of the rats, we will test the weight gain of the rats at 10% significance level with the use of Ti-83 calculator
The results from the One- way ANOVA ( Numerator )
with the use of Ti-83 calculator
F = .66853
p = .53054
Factor
df = 2 ( degree of freedom )
SS = 23.212
MS = 11.606
Results from One-way Anova ( denominator )
Ms = 11.606
Error
df = 12 ( degree of freedom )
SS = 208.324
MS = 17.3603
Sxp = 4.16657
where : test statistic = 0.6685
p-value = 0.53
level of significance ( ∝ ) = 0.10
The null hypothesis will be accepted because the P-value (0.53 ) > ∝
where Null hypothesis H0 = ∪1 = ∪2 = ∪3
hence The variance in weight is statistically the same among Javier's and Linda's rats
Answer:
25 posts
Step-by-step explanation:
So the number of fence post would be the total length of the log divided by the length of each post. As the log is 16m and is corrected to the nearest metre, it could possibly be 16.499m. As for the post that is 70 cm long and corrected to the nearest 10cm, it may as well be 65 cm (or 0.65m) each post
So the max number of fence point once can possibly cut from the log would be
16.499 / 0.65 = 25 posts
A. (−3, 3)
<span>3x – 4y = 21
</span>3(-3) - 4(3) = 21
-21 = 21 >>>>> not equal
B. (−1, −6)
<span>3(-1) - 4(-6) = 21
</span>21 = 21 >>>>>>>>>>Equal
C. (7, 0)
<span>3(7) - 4(0) = 21
</span>21 = 21>>>>>>>>>>equal
D. (11, 3)
<span>3(11) - 4(3) = 21
</span>21 = 21 >>>>>>>>>equal
