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Anna [14]
2 years ago
14

Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ

er in the box provided or use the upload option to submit your solution. (3,1) and (-2,3).
Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
7 0

The equation would be 2x + 5y = 11.

To find this, we first have to find the slope of the line. The slope formula is below.

m (slope) = (y2 - y1)/(x2 - x1)

In which (x1, y1) is the first point and (x2, y2) is the second. So we plug in to solve.

m = (3 - 1)/(-2 -3)

m = 2/-5

Now that we have the slope, we can use it along with a point to get the slope intercept form.

y = mx + b

3 = -2/5(-2) + b

3 = 4/5 + b

11/5 = b

Now that we have the equation of y = -2/5x + 11/5 we can manipulate it into standard form.

y = -2/5x + 11/5 -----> add 2/5x to both sides

2/5x + y = 11/5 ----> multiply both sides by 5

2x + 5y = 11

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Jlenok [28]

Answer:

0.78 Watts is correct answer.

Step-by-step explanation:

Formula:  

P=V*I  

=12*(6.5*10^-2)  

= 12*0.065  

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2 years ago
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The point (Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, StartFraction StartRoot 2 EndRoot Over 2 EndFraction)
Ierofanga [76]

Answer:

\cot(x)  =  - 1 \: and \:  \cos(x)  =  -  \frac{ \sqrt{2} }{2}

Step-by-step explanation:

The given point is :

( -  \frac{ \sqrt{2} }{2}, \frac{ \sqrt{2} }{2})

This point is in the second quadrant.

This means:

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Cotangent is cosine/sine

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2 years ago
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A waterbed filled with water has the dimensions 8ft by 7 ft by .75 ft taking the density of water to be 1.00/gm cubed how many k
monitta

By definition, the density is given by:

D = \frac{m}{V}

Where,

m: mass

V: volume

Clearing the mass we have:

m = DV

The volume is given by:

V = (8) * (7) * (0.75)

V = 42ft ^ 3

Then, we have the following conversion:

1foot = 0.3048m

Applying the conversion we have:

V = 42 * (0.3048) ^ 3

V = 1.19m ^ 3

On the other hand we have the following conversions:

1m = 100cm

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Applying the conversions for the density we have:

D = (1\frac{g}{cm^3})((\frac{100}{1})^3\frac{cm^3}{1m^3})(\frac{1}{1000}\frac{Kg}{g})=1000\frac{Kg}{m^3}

Then, the mass of the water is:

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1190 kilgrams of water are required to fill the waterbed

7 0
2 years ago
This table represents a quadratic function. x y 0 -3 1 -3.75 2 -4 3 -3.75 4 -3 5 -1.75 What is the value of a in the function’s
serg [7]

Answer:

a = 0.25

Step-by-step explanation:

Our strategy to solve this problem will be to use the information given in the table to obtain  first the value of c in the quadratic equation which has the form ax^2 + bx + c and then form a system of 2 linear equations  and solve for the coefficients a and b as follow:

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2a = 0.50 and substituting into any of the equations get b =  -1

so the quadratic equation has a= 0.25 b= -1  c= -3

we can even  plug the any of the other values for  x given in the table and check the answer.

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a)

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P=V÷(1+rt)...answer

b)

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