Step-by-step explanation:
its y-(-6)= 3 over 2(x-(-1))
Find x, y, and z such that x³+y³+z³=k, for each k from 1 to 100.
On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42? … I hope it helps you
The discrete uniform distribution is on the interval 8 ≤ x ≤ 10.
Therefore the probability density function (shown in the figure) is
P(x) = 1/3 = 1/3 for x = 8, 9, 10
= 0 otherwse
The mean is μ = 1/3.
The variance is
σ² = Σp(x) (x- μ)²
Because x - μ = 0 for x = 8,9,10, therefore
σ² = 0
Answer:
μ = 1/3
σ² = 0