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lapo4ka [179]
2 years ago
7

Percy buys tomatoes that cost $0.58 per pound he pays $2.03 for the tomatoes how many pounds of tomatoes does he buy show your w

ork using words pictures or numbers explain how you know your answer is reasonable
Mathematics
2 answers:
dlinn [17]2 years ago
7 0

Answer: 3.5 pounds


Step-by-step explanation:

Cost of 1 pound of tomatoes= $0.58

Thus, to find the quantity of tomatoes Percy bought in $2.03, we need to divide $2.03 by $0.58

⇒ The quantity of tomatoes he bought=\frac{\$2.03}{\$0.58}=\frac{203}{58}=\frac{35}{10}=3.5

⇒The quantity of tomatoes he bought = 3.5 pounds

Therefore, Percy bought 3.5 pounds of tomatoes .

Ksivusya [100]2 years ago
4 0
First you determine your unknown, the amount of pounds of tomatoes. We can set that to t, for tomatoes. Next, we know each pound is .58 dollars. We know if we multiple .58 t times, or the amount of pounds we have, we'll get the total price of 2.03. So our equation is
0.58*t=2.03.
Next, we isolate t to find out how many pounds were required to get the cost to 2.03. To isolate it, we do the inverse of .58*t, which is dividing, it, setting t to one.
2.03/.58=3.5
That means percy bought 3.5 pounds of tomatoes. That is reasonable, because (3*.5)+(.5*.5)=1.75, which is close to 2 dollars
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Answer:

Step-by-step explanation:

Corresponding fuel efficiencies of manufacturer A's car and manufacturer B's car form matched pairs.

The data for the test are the differences between the efficiencies of manufacturer A's car and manufacturer B's car

μd = fuel efficiency of manufacturer A's car minus the​ fuel efficiency of manufacturer B's car.

A B diff

32 28 4

27 22 5

26 27 - 1

26 24 2

25 24 1

29 25 4

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Sample mean, xd

= (4 + 5 - 1 + 2 + 1 + 4 + 3 - 2)/8 = 2

xd = 2

Standard deviation = √(summation(x - mean)²/n

n = 8

Summation(x - mean)² = (4 - 2)^2 + (5 - 2)^2 + (- 1 - 2)^2 + (2 - 2)^2 + (1 - 2)^2 + (4 - 2)^2 + (3 - 2)^2 + (- 2 - 2)^2 = 44

Standard deviation = √(44/8

sd = 2.35

For the null hypothesis

H0: μd = 0

For the alternative hypothesis

H1: μd ≠ 0

This is a two tailed test and the distribution is a students t. Therefore, degree of freedom, df = n - 1 = 8 - 1 = 7

2) The formula for determining the test statistic is

t = (xd - μd)/(sd/√n)

t = (2 - 0)/(2.35/√8)

t = 2.41

We would determine the probability value by using the t test calculator.

p = 0.047

Since alpha, 0.1 > the p value 0.047, then we would reject the null hypothesis. Therefore, at 1% significance level, we can conclude that there is a significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles.

6 0
2 years ago
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Pooja's plant began sprouting 2days before Pooja bought it, and she had it for 98 days until it died. At its tallest, the plant
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Given that function H(t) models the height of Pooja's plant (in centimeters) where t is the number of days after she bought it.

Now we have to find about which number type is more appropriate for the domain of h. That means what values can be taken by the variable "t".

Since t is number of days not the hours so t will not use decimal or fraction values. It can use integer values for the number of days.

Since time is counted after she bought the plant then number of days will be positive.

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4 0
2 years ago
Read 2 more answers
The wheel in the adjacent figure has a radius of 61 feet. The clearance between the wheel and the ground is 11 feet. The rectang
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Before the distribution of certain statistical software, every fourth compact disk (CD) is tested for accuracy. The testing proc
lilavasa [31]

Answer:

a) For this case we have 4 programs so then if we define the event R that a CD is tested we have the following probability for each test:

P(R) =\frac{1}{4} =0.25

The failure probability for each program are given by:

P(F_1) = 0.01 , P(F_2) = 0.03 , P(F_3) = 0.02 , P(F_4) = 0.01

For this case we assume that each test is independet form the others.

We can calculate the probability that all 4 programs works properly like this:

P(4 work) = (1-0.01)*(1-0.03)*(1-0.02)*(1-0.01)= 0.932

So then the probability that any program fails would be given by:

P(F) = 1- 0.932= 0.068

And if we use the fact that we have 4 possible test the true probability of interest would be:

P(R \cap F) = P(R)*P(F) = 0.25*0.068=0.017

b) p= P(F'_1) P(F'_4) *(1- P(F'_2)*P(F'_3))

And replacing we got:

p =(1-0.01)*(1-0.01) *[1- (1-0.03)(1-0.02)]= 0.99*0.99*[1- 0.97*0.98]= 0.0484

c) From part a we now that the probability that any program fails would be given by:

P(F) = 1- 0.932= 0.068

So then if we have 100 CDs the expected number of rejected Cd's are:

100*0.068= 6.8 \approx 7

Step-by-step explanation:

Part a

For this case we have 4 programs so then if we define the event R that a CD is tested we have the following probability for each test:

P(R) =\frac{1}{4} =0.25

The failure probability for each program are given by:

P(F_1) = 0.01 , P(F_2) = 0.03 , P(F_3) = 0.02 , P(F_4) = 0.01

For this case we assume that each test is independet form the others.

We can calculate the probability that all 4 programs works properly like this:

P(4 work) = (1-0.01)*(1-0.03)*(1-0.02)*(1-0.01)= 0.932

So then the probability that any program fails would be given by:

P(F) = 1- 0.932= 0.068

And if we use the fact that we have 4 possible test the true probability of interest would be:

P(R \cap F) = P(R)*P(F) = 0.25*0.068=0.017

Part b

For this case we want the probability that it failed program 2 or 3

So then we can find this probability like this:

p= P(F'_1) P(F'_4) *(1- P(F'_2)*P(F'_3))

And replacing we got:

p =(1-0.01)*(1-0.01) *[1- (1-0.03)(1-0.02)]= 0.99*0.99*[1- 0.97*0.98]= 0.0484

Part c

From part a we now that the probability that any program fails would be given by:

P(F) = 1- 0.932= 0.068

So then if we have 100 CDs the expected number of rejected Cd's are:

100*0.068= 6.8 \approx 7

3 0
2 years ago
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