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2 years ago

Will mark BRAINIEST. Solve this.

Mathematics

2 answers:

Alchen [17]2 years ago

4 0

Answers:

Equation is 3x+7 + 10x+17 = 180 (there are infinitely many other ways to write the equation)

x = 12

Angles are 43 and 137

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Explanation:

The horizontal lines are parallel, so the same side interior angles marked are supplementary. The angles add to 180

(3x+7) + (10x+17) = 180 is the equation, or one variation of such

13x+24 = 180

13x = 180-24

13x = 156

x = 156/13

x = 12 is the value of x

Use this x value to find the measure of each angle

3x+7 = 3*12+7 = 43

10x+17 = 10*12+17 = 137

The two angles are 43 and 137 degrees

Note how 43 and 137 add to 180.

Brums [2.3K]2 years ago

3 0

Answer:

3x+7=10x+17

Step-by-step explanation:

1.9

10x

27x

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Sum of positive roots of the equation (x2 - 12x + 35) (x2 + 10x + 24) = 504 is

Digiron [165]

Answer:

(3)11

Step-by-step explanation:

We are given that

$(x^2-12x+35)(x^2+10x+24)=504$

We have to find the sum of positive roots of the equation.

$x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504$

$x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504$

$x^4-2x^3-61x^2+62x+840-504=0$

$x^4-2x^3-61x^2+62x+336=0$

Factor of 336

2,3,4,6,8,7,

Let x=2

$2^4-2^4-61(2^2)+62(2)+336\neq0$

x=2 is not the root of equation

x=-2

$(-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0$

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

$3^4-2(3^3)-61(3^2)+62(3)+336=0$

Therefore, x=3 is the root of equation.

$(x+2)(x-3)(x^2-x-56)=0$

$(x+2)(x-3)(x^2-8x+7x-56)=0$

$(x+2)(x-3)(x(x-8)+7(x-8))=0$

$(x+2)(x-3)(x-8)(x+7)=0$

$x-8=0\implies x=8$

$x+7=0\implies x=-7$

Positive roots are 3 and 8

Sum of positive roots=3+8=11

Option (3) is true.

4 0

1 year ago

robert plant 7 trees behind westwood school. he planted 6 times as many trees in front of the school. how many trees did he plan

Sati [7]

49 in total or 42 trees in the front

4 0

2 years ago

Read 2 more answers

Evaluate the function f(x) = –2x2 – 3x + 5 for the input value –3.

Novosadov [1.4K]

Just so u know, ur output value is f(x) and ur input value is x

f(x) = -2x^2 - 3x + 5....when ur input value(x) is -3

f(-3) = -2(-3^2) - 3(-3) + 5 =
f(-3) = -2(9) + 9 + 5
f(-3) = -18 + 14
f(-3) = -4 <==

4 0

1 year ago

Read 2 more answers

A pile of coins, consisting of quarters and half dollars, it worth $11.75. If there are 2 more quarters than half dollars, how m

lord [1]

Let the number of half dollars be x,

number of quarters = x + 2
amount of half dollars = 0.5x
amount of quarters = 0.25(x + 2)
= 0.25x + 0.5
total amount = 0.5x + 0.25x + 0.5
= 0.75x + 0.5
0.75x + 0.5 = 11.75
0.75x = 11.25
x = 15
number of quarters = x + 2
= 15 + 2
= 17

There are 17 quarters and 15 half dollars.

3 0

2 years ago

On a website selling books, three paperback books and five hardcover books cost $80.10, and seven paperback books and four hardc

Lisa [10]

To answer this kind of question, you need to insert the first equation into second equation or vice versa. The equation from the question should be:

1. 3 paperback books + 5 hardcover book = $80.10
2. 7 paperback books + 4 hardcover book= $100.65

It would be easier to convert the 1st equation into
5 hardcover book = $80.10- 3 paperback books
hardcover book= $16.02- 0.6 paperback books

Then insert it to 2nd equation:
7 paperback books + 4 ($16.02- 0.6 paperback books)= $100.65
7 paperback books + $64.08- 2.4 paperback books= $100.65
4.6 paperback books = $100.65- $64.08= $36.57
paperback book= $7.95

Insert paperback book price to the first equation to find the hardcover book price
3 paperback books + 5 hardcover book = $80.10
3 ($7.95)+ 5 hardcover book = $80.10
5 hardcover book = $80.10 - $23.85= $56.25
hardcover book = $11.25

Then one paperback and one hardcoverbook= $7.95 + $11.25= $19.20

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2 years ago