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storchak [24]
1 year ago
13

A cone has a slant length of 5 and a diameter of 4. What is the volume of the cone? Use π ≈ 3.14.

Mathematics
2 answers:
Olegator [25]1 year ago
3 0

Answer:

V = 19.19 cubic units

None of the options are correct.

Step-by-step explanation:

Volume of a cone is given as;

V = ⅓πr²h

Now, we are given;

diameter = 4 units

Thus radius;r = diameter/2 = 4/2 = 2 units

I have attached an image to show the diagram of the cone.

Now, to find the height (h), we know the radius(r) and we know the slant length(l) . So we can use Pythagoras theorem to find the height.

From Pythagoras theorem;

r² + h² = l²

Where l is the hypotenuse or the slant side while "r" is the radius of the cone while the height will be "h"

Thus;

2² + h² = 5²

h² = 5² - 2²

h² = 25 - 4

h² = 21

h = √21

h = 4.5826 units

So height (h) = 4.5826 units

Volume of cone;V = ⅓πr²h

We are told that π = 3.14

Thus;

V = ⅓ x 3.14 x 2² x 4.5826

V = 19.19 cubic units

Gennadij [26K]1 year ago
3 0

Answer:A on edge

Step-by-step explanation:

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Answer:

hannah gets £56

Step-by-step explanation:

z   : h

3   : 7

24 : ?

24/3 = 8

8 x 7 = 56

£56

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Roberto's toy car travels at 30 centimeters per second (cm/sec) at high speed and 20 cm/sec at low speed. If the car travels for
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Step-by-step explanation:

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An ice cream store has two new flavors: Fantasy and Ecstasy. Each barrel of Fantasy requires 4
Y_Kistochka [10]

Answer:

  • Fantasy: 3 barrels
  • Ecstasy: 1 barrel

Step-by-step explanation:

<u>Given</u>

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  Ecstasy uses 4 lb of nuts, 1 lb of chocolate, for a profit of $40

  In stock are 16 lb of nuts, 10 lb of chocolate

<u>Find</u>

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<u>Solution</u>

Let x and y represent barrels of Fantasy and Ecstasy, respectively. Then the limitations on production are ...

  4x +4y ≤ 16 . . . lb of nuts

  3x +y ≤ 10 . . . . lb of chocolate

We want to maximize

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The graph shows the feasible region. Its vertices are ...

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8 0
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Lera brought a watermelon that weighed b kg to a party. Nick brought a box of candies. How much is the weight of the box of cand
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Answer:

1.5b (kg)

Step-by-step explanation:

Let's begin by listing out the variables we were given:

weight of the watermelon = b (kg),

weight of watermelon = (2/5) * weight of candies

weight of candies = 1 ÷ (2/5) = 1 ÷ 0.4

weight of candies = 2.5b (kg)

How much is the weight of the box of candies greater than the weight of the watermelon is given by:

weight of the box of candies - weight of watermelon= 2.5b - b = <u>1.5b</u> (kg)

<u>Therefore, the weight of the box of candies is greater than the weight of the watermelon by 1.5b (kg) </u>

7 0
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