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Inessa05 [86]
2 years ago
5

Quadrilateral ABCD is inscribed in circle P as shown. Which statement is necessarily true? A. `"m"/_A +"m"/_B = "m"/_C + "m"/_D

` B. `"m"/_A + "m"/_C = "m"/_B + "m"/_D ` C. `"m"/_A + "m"/_D = "m"/_B + "m"/_C` D. `"m"/_A + "m"/_B = 2("m"/_C + "m"/_D) `
Mathematics
1 answer:
pogonyaev2 years ago
3 0

Opposite angles of an inscribed quadrilateral are supplementary, so it is true that ...

... B. m∠A + m∠C = m∠B + m∠D . . . . . = 180°

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The floor area of a hall is 1044 m2. The length is 36 m. Give a quick estimate of width of the hall. ?
wolverine [178]
36m. Im not sure but thats what i got, hope it helps...
4 0
2 years ago
Help me with this question please!
BigorU [14]

Answer:

c = 40d+20

Step-by-step explanation:

He has to pay 20 dollars and that can't multiply so the forty has to multiply and it would have to be by d because c is the total cost

6 0
2 years ago
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Wheel A has a diameter of 25.4 inches. Wheel B has a diameter of 22.5 inches. About how much farther will Wheel A travel in one
MissTica

Wheel A will travel a distance of approximately 9 in more than wheel B in one rotation.

<u>Explanation:</u>

Given:

Diameter of wheel A, d₁ = 25.4 in

Radius of wheel A, r₁ = 12.7 in

Diameter of wheel B = 22.5 in

Radius of Wheel B, d₂ = 11.25 in

Distance travelled by A = ?

In one rotation, the distance travelled by a wheel is equal to its circumference.

Circumference of a wheel = 2πr

Circumference of wheel A = 2πr₁

                                            = 2 X 3.14 X 12.7 in

                                            = 80 in

Circumference of wheel B = 2πr₂

                                              = 2 X 3.14 X 11.25 in

                                              = 71 in

Therefore, wheel A will travel a distance of approximately 9 (80 - 71 in) in more than wheel B in one rotation.

3 0
2 years ago
the points A (1, 5), B (5, 5) and C (5, 1) are 3 corners of a square ABCD. what are the coordinates of D, the 4th corner
bogdanovich [222]

Answer:

(1,1)

This is the answer

3 0
2 years ago
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1. H+S=40

2. 19H+25S=922

From 1,

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Subtract this from 2 to eliminate H,

19H+25S-19H-19S=922-760

6S=162

Solve for S, then use either equation to solve for H.

4 0
2 years ago
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