NEED HELP ASAP!!! ON A KHAN ACADEMY TEST AND DON"T HAVE MUCH TIME LEFT!!! CORRECT ANSWER GETS BRAINLIEST!!!
1 answer:
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Answer:
35.2% probability that the sample mean will be 246 pages or more
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question, we have that:
What the probability that the sample mean will be 246 pages or more?
This is 1 subtracted by the pvalue of Z when X = 246. So
By the Central Limit Theorem
has a pvalue of 0.6480.
1 - 0.6480 = 0.3520
35.2% probability that the sample mean will be 246 pages or more
Answer:
The statement provided is True.
Step-by-step explanation:
The exponential function representing growth is given as follows:
Here,
<em>y</em> = final value
<em>y</em>₀ = initial value
<em>k</em> = growth rate
<em>t</em> = time passed
As the function is increasing, then the exponential function representing growth is also increasing.
Thus, the statement provided is True.