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2 years ago

Select the correct answer.

Mathematics

2 answers:

lakkis [162]2 years ago

8 0

Answer:

6x + 4y ≤ 50

x + y ≥ 10

Step-by-step explanation:

$6 is the cost of stuffed animals $4 is the cost of toy trucks and the her maximum budget is $50 it would be 6x+4y is less then or equal to 50 and there is AT LEAST 10 people so the amounts which are x and y would be equal to or greater than 10.

olga2289 [7]2 years ago

8 0

Answer:

$6x+4y\leq 50$

$x+y\geq 10$

Step-by-step explanation:

$x$ represents the number of stuffed animals.

$y$ represents the number of toy trucks.

Now, according to the problem, she found stuffed animals for $6.00 each and toy trucks for $4.00 each. Also, Laura has a restricted budget of $50. All these can be expressde as

$6x+4y\leq 50$

Also, the problem states that Laura wants to provide one partu favor per person to at least 10 people, that means

$x+y\geq 10$ , because "at least" represents a minimum value, which is expressed with $\geq$ .

Therefore, the inequality system that models this situation is

$6x+4y\leq 50$

$x+y\geq 10$

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Firstly, Convert metre to centimetre

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Of the 400 eighth-graders at pascal middle school, 117 take algebra, 109 take advanced computer, and 114 take industrial technol

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If 164 of the 400 eighth-graders take none of these courses, then 400-164=236 students take some courses.

Let x students take all three courses, then:

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2. 34-x take only both algebra and industrial technology,

3. 29-x take only both advanced computer and industrial technology.

Now let's count how many student take only one course:

1. 117-(x+34-x+70-x)=13+x take algebra,

2. 109-(x+29-x+70-x)=10+x take advanced computer,

3. 114-(x+29-x+34-x)=51+x take industrial technology.

Now count all students that take some courses:

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Answer:

Step-by-step explanation:

To complete the question, here are the answer choices:

A) =A1*A2*A3*A4

B) =A1*A2+A3+A1*A4

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D) =A1*A2+(A3+A1)*A4

We first need to multiply A1 and A2, this will give weight of passengers.

To get weight of luggage, we multiply A1 and A4.

We also need the checked weight to add to that, which is in A3. So then we add up A3 with those 2.

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A1*A2 + A1*A4 + A3

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snow_tiger [21]

Let us assume uniform width = x cm wide.

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Therefore, length of rectangle made by frame = 50 + x+x = (2x+50) cm.

And width of rectangle made by frame = 70+x+x = (2x+70) cm.

We know, the area of rectangular portrait = 50 × 70 = 3500 cm^2.

Total area of the rectangle made by frame would be = (2x+50) * (2x+70)

We know,

Actual area of frame = Area of rectangle made by frame - area of rectangular portrait.

We also given "the area of the frame is the same as the area of the portrait."

We can setup an equation now,

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Subtracting 3500 from both sides, we get

3500-3500 = (2x+50) * (2x+70) - 3500-3500.

0 = (2x+50) * (2x+70) -7000.

FOIL (2x+50) * (2x+70), we get

0 = 2x*2x +2x*70 + 50*2x +50*70 - 7000.

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4x^2 +240x -3500 = 0.

Dividing whole equation by 4, we get

x^2 +60x - 875 =0

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$=\frac{-60\pm \sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}$

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We could take approximately 12 cm.

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