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sladkih [1.3K]
2 years ago
6

The conditional relative frequency table below was generated by column using data comparing gender and a person's favorite meal

to cook.
A 5-column table with 3 rows. The first column has no label with entries male, female, total. The second column is labeled breakfast with entries A, E, 1.0. The third column is labeled lunch with entries B, F, 1.0. The fourth column is labeled dinner with entries C, G, 1.0. The fifth column is labeled total with entries D, H, 1.0.
Which would most likely indicate an association between the categorical variables?

The value of A is similar to the value of B.
The value of A is similar to the value of E.
The value of B is not similar to the value of C.
The value of B is not similar to the value of F.
Mathematics
2 answers:
monitta2 years ago
8 0

Answer:

The value of B is not similar to the value of C.

Step-by-step explanation:

unit test review edge2020 lol

goblinko [34]2 years ago
5 0

Answer:

The answer is C

Step-by-step explanation:

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Kari is flying a kite. She releases 50 feet of string. What is the approximate difference in the height of the kite when the str
nirvana33 [79]
Sinα=h/L  where h=height, L=string length...

h=Lsinα  so

h(25°)=50sin25≈21.1ft

h(45°)=50sin45≈35.4ft
5 0
2 years ago
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Tobias gold sells computers at the office Center he's guaranteed a minimum salary of $1,959 per month plus 6.3% commission on to
ICE Princess25 [194]

Answer:2269.95

Step-by-step explanation:

You would take 1,959 and divide it by 6.3. The answer of that will be added to 1,959. And that's how I got the answer good luck! And I hope that this helps.


Also quick note 2269.95 is how much is made in a month! :)



6 0
2 years ago
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In equilateral ∆ABC with side a, the perpendicular to side AB at point B intersects extension of median AM in point P. What is t
Sergeeva-Olga [200]

Answer:

Perimeter  = (2 + √3)·a

Step-by-step explanation:

Given: ΔABC is equilateral and AB = a

The diagram is given below :

AM is a median , PB ⊥ AB , PM = b

Now, by using properties of equilateral triangle, median is perpendicular bisector and each angle is of 60°.

We get, ∠AMB = 90°. So, by linear pair ∠AMB + ∠PMB = 180° ⇒ ∠PMB = 90°. Also, ∠ABC = 60° and ∠ABP = 90° (given) So, ∠PBM = 30°

Since, AM is perpendicular bisector of BC. So,

MB = \frac{a}{2}

Now in ΔAMB , By using Pythagoras theorem

AB^{2}=AM^{2}+MB^{2}\\AM^{2}=AB^{2}-MB^{2}\\AM^{2}=a^{2}-(\frac{a}{2})^{2}\\AM=\frac{\sqrt{3}\cdot a}{2}

Now, in ΔBMP :

sin\thinspace 30^{o}=\frac{\text{Perpendicular}}{\text{Hypotenuse}}\\\\sin\thinspace 30^{o}=\frac{\text{MB}}{\text{PB}}\\\\PB=\frac{\text{MB}}{\text{sin 30}}\\\\PB=\frac{\frac{a}{2}}{\frac{1}{2}}\implies PB = a\\\\tan\thinspace 30^{o}=\frac{\text{Perpendicular}}{\text{Base}}\\\\tan\thinspace 30^{o}=\frac{\text{MB}}{\text{PM}}\\\\PM=\frac{\text{MB}}{\text{tan 30}}\\\\PM=\frac{\frac{a}{2}}{\frac{1}{\sqrt3}}\implies PM=b= \frac{\sqrt{3}\cdot a}{2}

Perimeter of ABM = AB + PB + PM + AM

\text{Perimeter = }a+a+b+ \frac{\sqrt{3}\cdot a}{2}\\\\=2\cdot a + \frac{\sqrt{3}\cdot a}{2} +\frac{\sqrt{3}\cdot a}{2}\\\\=2\cdot a +\sqrt{3}\cdot a\\\\=(2+\sqrt3})\cdot a

Hence, Perimeter of ΔABP = (2 + √3)·a units

3 0
1 year ago
Cecily is comparing two checking accounts. Checking account A has a monthly fee of $16 and a per-check fee of $0.08, while check
Tpy6a [65]

Answer:

(1) 0.08x + 16

(2) 0.08x + 16=0.12x + 14

Step-by-step explanation:

Checking account A has a monthly fee of $16 and a per-check fee of $0.08

Per check fee is a constant rate that is 0.08

Let x represents the number of checks Cecily writes per month

1 check fee = 0.08

x checks fee = 0.08x

monthly fee is $16 , we add that as well

So total monthly fee charges for account A  is

0.08x + 16

checking account B has monthly fee of $14 and a per-check fee of $0.12.

1 check fee = 0.12

x checks fee = 0.12x

monthly fee is $14 , we add that as well

So total monthly fee charges for account B  is

0.12x + 14

(2) To find number of checks write per month for the accounts to charge the same in fees

WE set both expression , account A = account B

0.08x + 16=0.12x + 14

Subtract 0.12x on both sides

-0.04x + 16 = 14

Now subtract 16 on both sides

-0.04x = -2

Divide by -0.04 on both sides

So x= 50



7 0
2 years ago
For the given cost function C(x), find the oblique asymptote of the average cost function C(X), C(x)=14,000+94x+0.03x^2
marusya05 [52]
Answer: y = 0.03x + 94

--------------------------------------

Explanation:

Lets define A(x) to be the average cost function where 
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basically you divide the given cost function C(x) by the number of units produced (x)

Dividing C(x) over x leads to:
A(x) = C(x)/x
A(x) = (14000+94x+0.03x^2)/x ... substitution
A(x) = (0.03x^2+94x+14000)/x ... rearrange terms
A(x) = (0.03x^2)/x+(94x)/x+(14000)/x ... break up the fraction
A(x) = 0.03x + 94 + (14000/x) ... simplify

If x were to head off to infinity, then the portion 14000/x approaches 0. 

So this is why the oblique asymptote is y = 0.03x + 94

Basically, in the long run, the average cost will approach y = 0.03x + 94

5 0
2 years ago
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