What is the pattern of 3.5, 13, 41.5, 127,,,, and the anwser

Mathematics

2 answers:

maw [93]2 years ago

8 0

Times 3 plus 2.5 is the pattern, and the next number is 383.5

beks73 [17]2 years ago

3 0

Answer with Step-by-step explanation:

We are given a sequence as:

3.5, 13, 41.5, 127,...

we have to determine the pattern

13= 3.5×3+2.5

41.5= 13×3+2.5

127= 41.5×3+2.5

Hence, the sequence is defined as next term in the sequence is 3 times the previous term of the sequence plus 2.5

i.e. $a_{n+1} =3a_{n} +2.5\ ;\ a_{1}=3.5$

Hence, Pattern is:

$a_{n+1} =3a_{n} +2.5\ ;\ a_{1}=3.5$

You might be interested in

Estimate the diameter of the supergiant star Betelgeuse, using its angular diameter of about 0.05 arcsecond and distance of abou

8090 [49]

0.05 arc-second = 1 degree/72000 = (pi radians)/(180*72000) = 2.424 x 10^(-7) radians

The distance is roughly:

R*(theta) = (600 light-years)*2.424 x 10^(-7) = 0.00014544 light-years = 1.275 light-hours = (3600 seconds)*(3 x 10^8 m/s)*(1.275) = 1.38 x 10^12 meters.

7 0

2 years ago

Read 2 more answers

ABCD ~ EFGH z=? Please help me!!!

iragen [17]

Answer:

z = 110°

Step-by-step explanation:

Since the figures are similar, then corresponding angles are congruent, thus

∠H = ∠D, that is

z = 110°

5 0

2 years ago

Suppose that – in any given time period – a certain stock is equally likely to go up 1 unit or down 1 unit, and that the outcome

Scorpion4ik [409]

Answer:

Step-by-step explanation:

From the given information:

Let X represent the amount of the stock that goes up in the first period; &

Let Y denote the cumulative amount that goes up in the first three periods.

Then,

$X= X_1 + X_2 \\ \\ \\EX= EX_1 +EX_2\\ \\\\Now ; EX = 0 \\ \\ EX = \dfrac{1}{2}\times 1 + \dfrac{1}{2}\times -1 \\ \\ EX = \dfrac{1}{2}-\dfrac{1}{2} \\ \\ EX = 0$