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1 year ago

According to the graph of H(w) below, the w-axis is also the _____ for H(w).

Mathematics

2 answers:

klemol [59]1 year ago

4 0

Independent variable. It is also called abscissa.

Alexxandr [17]1 year ago

3 0

The answer is Horizontal asymptote

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One slice of cheese pizza contains 310 calories. A medium-size orange has one-fifth that number of calories. How many calories a

I am Lyosha [343]

The medium sized orange would have 62 calories. To divide by 1/5, which in decimal form is 0.2, you just multiply 310 by 0.2, therefore, giving you 62. Hope this helps!

7 0

2 years ago

Read 2 more answers

Colin gets pic 'n mix when at the cinema and makes his bag up with 3 types of sweet. He pick:

Kisachek [45]

Answer: 2/3

Explanation: Assume that the number of smarties he picked is c.

Now, we are given that:

1- He picked 3 times as many cola bottles as smarties. This means that:

Number of cola bottles he picked = 3s

2- He picked twice as many smarties as marshmallows. This means that:

number of marshmallows he picked = 0.5s

Now to get the proportion o f cola bottles, we will divide the number of cola bottles by the total number of sweets as follows:

proportion of cola bottles =

Hope this helps :)

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1 year ago

Determine the area (in units2) of the region between the two curves by integrating over the x-axis. y = x2 − 24 and y = 1

astra-53 [7]

Answer:

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

Step-by-step explanation:

This case represents a definite integral, in which lower and upper limits are needed, which corresponds to the points where both intersect each other. That is:

$x^{2} - 24 = 1$

Given that resulting expression is a second order polynomial of the form $x^{2} - a^{2}$ , there are two real and distinct solutions. Roots of the expression are:

$x_{1} = -5$ and $x_{2} = 5$ .

Now, it is also required to determine which part of the interval $(x_{1}, x_{2})$ is equal to a number greater than zero (positive). That is:

$x^{2} - 24 > 0$

$x^{2} > 24$

$x < -4.899$ and $x > 4.899$ .

Therefore, exists two sub-intervals: $[-5, -4.899]$ and $\left[4.899,5\right]$ . Besides, $x^{2} - 24 > y = 1$ in each sub-interval. The definite integral of the region between the two curves over the x-axis is:

$A = \int\limits^{-4.899}_{-5} [{1 - (x^{2}-24)]} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} [{1 - (x^{2}-24)]} \, dx$

$A = \int\limits^{-4.899}_{-5} {25-x^{2}} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} {25-x^{2}} \, dx$

$A = 25\cdot x \right \left|\limits_{-5}^{-4.899} -\frac{1}{3}\cdot x^{3}\left|\limits_{-5}^{-4.899} + x\left|\limits_{-4.899}^{4.899} + 25\cdot x \right \left|\limits_{4.899}^{5} -\frac{1}{3}\cdot x^{3}\left|\limits_{4.899}^{5}$