Solution: We are given:
Total students = 10 + 30 + 10 =50
Number of students who received A grade = 3 + 10 + 5 = 18
Number of senior student's who received A grade is = 10
Let A be the event that the student is senior and B be the event that he or she earned an A. Then,
Now the probability a student chosen at random from this class and is found to have earned an A, the probability that he or she is a senior is:
The given data is the following:
Student Trial 1 Trial 2 Trial 3 Average
----------- -------- -------- -------- ------------
1 66.0 66.5 68.5 67.0
2 67.5 64.0 70.5 67.3
3 60.3 60.5 60.5 61.0
4 55.0 58.0 59.0 57.3
Let us check the reported averages.
Student 1:
Average = (66.0 + 66.5 + 68.5)/3 = 67.0 Correct
Student 2:
Average = (67.5 + 64.0 + 70.5)/3 = 67.3 Correct
Student 3:
Average = (60.3 + 60.5 + 60.5)/3 = 604 Incorrect
Student 4:
Average = (55.0 + 58.0 + 59.0)/3 = 57.3 Correct
Answer: Student 3
Let x = 63.63...(by repeating i assume you mean the 63 is repeated as 63.636363...)
therefore 100x = 6363.63..
100x-x =6300 (the recurring bit has been cancelled out which is what you should always aim to do)
99x=6300
x = 6300/99
cancel down
x = 700/11
Answer:
who is nathan
Step-by-step explanation:
do u know her
Regular size saves $0.0003 per gram I think
someone pls fact check me
