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2 years ago

Marissa is drawing coins from a bag that contains 5 pennies, 4 nickels, 5 m

2 answers:

6 0

a. Calculate the sum of all the coins combined = 5 + 4 + 5 + 2 =16. Then put the nickels over the sum = 4/16 = 1/4 = 0.25 = 25%

b. Add the new coins to the sum = 4/20 = 1/5 = 0.20 = 20%

c. She is more likely to draw a nickel in scenario A.

SIZIF [17.4K]2 years ago

5 0

Answer:

Step-by-step explanation:

Total no of coins in the bag $= 5+4+5+2 =16$

a) the probability that she will draw a nickel=no of nickels/total coins

= $\frac{4}{16} =0.25$

If one penny, two dimes and one quarter added then we have total coins new as = $16+1+2+1 = 20$

the

new probability that Marissa will draw a nickel= new nickel coins/new total

= $\frac{4+0}{20} =0.20$

IN the first situation there is more likely as probability is more.

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Suppose that water is pouring into a swimming pool in the shape of a right circular cylinder at a constant rate of 8 cubic feet

adell [148]

Answer:

dh/dt = 0,07 ft/min

Step-by-step explanation:

The swimming pool has the shape of right circular cylinder, therefore its volume is

V(c) = π*x²*h

Where x is the radius of the base and h the height

We take differentiation on both sides of the equation to get:

dV/dt = π*x²*dh/dt

The rate of change in height of water in the pool, is independent of the height of the water, since the pool is a right crcular cylinder, and dV/dt is constant at 8 ft³/min.

Then:

8 = π*x²*dh/dt

dh/dt = 8 / π*x²

dh/dt = 8/113,04

dh/dt = 0,07 ft/min

7 0

2 years ago

Suppose babies born in a large hospital have a mean weight of 3316 grams, and a standard deviation of 324 grams. If 83 babies ar

Anuta_ua [19.1K]

Answer: 0.129

Step-by-step explanation:

Let $\overline{X}$ denotes a random variable that represents the mean weight of babies born.

Population mean : $\mu= \text{3316 grams,}$

Standard deviation: $\text{324 grams}$

Sample size = 83

Now, the probability that the mean weight of the sample babies would differ from the population mean by greater than 54 grams will be :

$P(|\mu-\overline{X}|>54)=1-P(\dfrac{-54}{\dfrac{324}{\sqrt{83}}}$

hence, the required probability = 0.129

5 0

2 years ago

Solve for x in the equation x squared + 11 x + StartFraction 121 Over 4 EndFraction = StartFraction 125 Over 4 EndFraction.

Ira Lisetskai [31]

Answer:

Below

Step-by-step explanation:

● x^2 + 11x + 121/4 = 125/4

Substract 125/4 from both sides:

● x^2 + 11x + 121/4-125/4= 125/4 -125/4

● x^2 + 11x - (-4/4) = 0

● x^2 +11x -(-1) = 0

● x^2 + 11 x + 1 = 0

This is a quadratic equation so we will use the determinanant (b^2-4ac)

● a = 1

● b = 11

● c = 1

● b^2-4ac = 11^2-4*1*1 = 117

So this equation has two solutions:

● x = (-b -/+ √(b^2-4ac) ) / 2a

● x = (-11 -/+ √(117) ) / 2

● x = (-11 -/+ 3√(13))/ 2

● x = -0.91 or x = -10.9

Round to the nearest unit

● x = -1 or x = -11

The solutions are { -1,-11}

6 0

2 years ago

Read 2 more answers

An oblique prism has trapezoidal bases and a vertical height of 10 units. An oblique trapezoidal prism is shown. The trapezoid h

hichkok12 [17]

Answer:

30x² cubic units

Step-by-step explanation:

The volume of an Oblique prism = Base Area × Height

This oblique prism has trapezoidal bases.

Area of a Trapezoid = 1/2 × h × ( b1+b2)

where h = height

b1 and b2 = bases of the Trapezoid.

From the question,

h = 20

b1 = x

b2 = 2x

Area of the Trapezoid =

1/2 × x ×( x + 2x)

1/2 × x × (3x)

3x²/2 square units.

Remember, the volume of an Oblique prism = Base Area × Height

Height of the prism = The distance between the 2 trapezoid bases = 20 units.

Base Area = 3x²/2 square units × 20 units

= 30x² cubic units

3 0

2 years ago

Hey ^-^ can someone please help me with this problem:

soldi70 [24.7K]

Answer: 8 (Pi - sqrt(3))

Discussion:

The area of the shaded region is that of the semicircle minus the area of the triangle..

Area of semicircle = 1/2 * Pi * R^2

Where R^2 is the square of the radius of the circle. In our case, R ( = OC)

= 4 so the semicircle area is

(1/2) * Pi * (4^2) = (1/2) * Pi * 16 = 8 Pi

Area of triangle.

First of all, angle ACB is a right angle ( i.e. 90 degrees).

* This is the Theorem of Thales from elementary Plane Geometry. *

so by Pythagoras

AC^2 + BC^2 = AB^2

But CB = 4 (given) and AB = 4*2 = 8 ( the diameter is twice the radius).

Substituting these in Pythagoras gives

AC^2 + 4^2 = 8^2 or

AC^2 = 8^2 - 4^2- = 64 - 16 = 48

Hence AC = sqrt(48) = sqrt (16*3) = 4 * sqrt(3)

We are almost done! The area of the triangle is given by

(1/2) b * h = (1/2) BC * AC = (1/2) 4 * (4 * sqrt(3)) = 8 sqrt(3)

We conclude the area area of the shaded part is

8 PI - 8 sqrt(3) = 8 (Pi - sqrt(3))

Note that sqrt(3) is approx 1.7 so (PI - sqrt(3)) is a positive number, as it better well be!

6 0

2 years ago