Answer:
$393.50+/-$19.72
= ( $373.78, $413.22)
Therefore, the 95% confidence interval (a,b) = ($373.78, $413.22)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = $393.50
Standard deviation r = $50.30
Number of samples n = 25
Confidence interval = 95%
z value(at 95% confidence) = 1.96
Substituting the values we have;
$393.50+/-1.96($50.30/√25)
$393.50+/-1.96($10.06)
$393.50+/-$19.7176
$393.50+/-$19.72
= ( $373.78, $413.22)
Therefore, the 95% confidence interval (a,b) = ($373.78, $413.22)
Answer:
Step-by-step explanation:
The equation that models the height of the ball in feet as a function of time is

Where
is the initial height,
is the initial velocity and t is the time in seconds.
We know that the initial height is:
The initial speed is:

So the equation is:

The ball hits the ground when when
So

We use the quadratic formula to solve the equation for t
For a quadratic equation of the form

The quadratic formula is:

In this case

Therefore

We take the positive solution.
Finally the ball takes 2.47 seconds to touch the ground
Answer:
i dont know the answer
Step-by-step explanation:
just put a random answer and hope for the best
Jalen has total 63 comic books.
Step-by-step explanation:
Given,
Total value of comic books = $3135
Let,
Number of $45 comic books = x
Number of $65 comic books = y
According to given statement;
45x+65y=3135 Eqn 1
x=y+33 Eqn 2
Putting value of x from Eqn 2 in Eqn 1

Dividing both sides by 110

Putting y=15 in Eqn 2

Total comic books = x+y
Total comic books = 48+15 = 63
Jalen has total 63 comic books.
Keywords: addition, elimination method
Learn more about elimination method at:
#LearnwithBrainly
Answer:
Let t be the number of ten dollar bills.
o×6+5=t
If you need it without t, then it's:
o×6+5
Step-by-step explanation:
Let t be the number of ten dollar bills.
o×6+5=t
We get this because the question said that there were more ten-dollar bills than 6 times the number of one-dollar bills.