This will be your equation:
18+.5n.
18 flat fee, .5 (50) cent for every call.
For this case we have the following definition:

Where,
d: distance
v: speed
t: time
Clearing the time we have:

The total driving time takes half an hour:

Clearing d we have:
Answer:
she lives 18 miles far from the store
Answer:
am i supposed to do area? volume? circumfrence?
Answer:
StartFraction 1 Over 15 EndFraction left-parenthesis 10 h plus 60 right-parenthesis equals StartFraction 1 Over 10 Endfraction left-parenthesis 10 h right-parenthesis
Step-by-step explanation:
The desired equation equates 1/15 of the amount Lindsay earned with 1/10 the amount without the bonus:
StartFraction 1 Over 15 EndFraction left-parenthesis 10 h plus 60 right-parenthesis equals StartFraction 1 Over 10 Endfraction left-parenthesis 10 h right-parenthesis
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Answer:
The dimensional analysis method uses equivalences written in <u>fractional</u> form. Because the numerator and denominator of the fraction are equivalent, the value of the fraction is <u>1.</u> Multiplying by 1 does not change the quantity, but using an equivalence will change the units (or label). In order for units to cancel they must be in <u>the numerator and the denominator</u> of the fraction
Step-by-step explanation:
Dimensional analysis is a method of problem solving that takes into consideration the identity property of multiplication whereby the product of a number and 1 will always give the same number, that is 1 × n = n whereby the value "n" remains the same after the multiplication
Therefore, a fraction of two equivalent measurements but different units has a value of 1, and multiplying the equivalent fraction with another measurement with the same unit as the denominator of the fraction with a value of 1 changes the unit to that of the unit of the numerator