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Maksim231197 [3]
2 years ago
11

Ivy and cammie sold tulip and daffodil bulb packages for their spring fundraiser. Ivy sold 12 packages of tulip bulbs (X) and 14

packages of daffodils bulbs (y) for a total of $180.00. Cammie sold 9 packages of tulip bulbs and 16 packages of daffodils bulbs for a total of $168. Which system of linear equations can be used to find the price per package for each of the two kinds of bulbs ?
A) 12x + 14y = 168
9x + 16y = 168

B) 9X + 14y = 180
12X + 16y = 168

C) 12X + 16y = 180
9X + 14y = 168

D) 12X + 14y = 180
9X + 16y = 168
Mathematics
2 answers:
Digiron [165]2 years ago
3 0

Answer:

D)

Step-by-step explanation:

because we need to find the each so its x and y?

Viefleur [7K]2 years ago
3 0

Answer:

D

Step-by-step explanation:

Because ivy sold 12 tulip bulbs for the price of (x) and 14 packages of daffodils bulbs for (y) and that total was $180.

Same thing was done for the bottom equation

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What is the area of a circle with 11m and 9m?
Naya [18.7K]

Answer:

99m

Step-by-step explanation:

multiply the two numbers

3 0
2 years ago
When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected
jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

N=\frac{12.36}{0.03+0.55^t}

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

N=\frac{12.36}{0.33+0.55^0}

N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12

A. Initially, there were 12 deer.

B. N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

8 0
2 years ago
Which statement describes a process to solve sqrt b+20 - sqrt b=5?
babunello [35]

Answer:

Step-by-step explanation:

The equation is:

√b+20 - √b = 5

The first step is we will add √b to both sides:

√b+20 -√b +√b = 5 +√b

√b+20 = 5+√b

Now take square at both sides:

(√b+20)^2 = (5+√b)^2

b+20 = 25+10√b+b

Now combine the like terms:

b+20-25-b=10√b

-5 = 10√b

Divide both the terms by 10

-5/10 = 10√b/10

-1/2=√b

Take square at both sides:

(-1/2)^2 = (√b)^2

1/4 = b

So in this type of question we add radical terms to both sides and square both sides twice....

7 0
2 years ago
myra swims 3/5 of a mile farther than luke.if luke swims 2 and 4/10 miles, how many milrs does myra swim?
Dmitry [639]
Myra swims 3/5 of mile so that is .6 miles 
8 0
2 years ago
Read 2 more answers
Ramona put her dog, butch, on a diet for 5 months. at the end of the diet, butch's total weight change was −11 1/5 pounds. what
Lady_Fox [76]
(-11 1/5) / 5 =
(-56/5) / 5 =
-56/5 * 1/5 =
-56/25 =
- 2 6/25 <===
6 0
2 years ago
Read 2 more answers
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