Question

Ramona put her dog, butch, on a diet for 5 months. at the end of the diet, butch's total weight change was −11 1/5 pounds. what was butch's average weight change each month of the diet? enter your answer as a mixed number, in simplified form, in the box.

Answer 1

(-11 1/5) / 5 =
(-56/5) / 5 =
-56/5 * 1/5 =
-56/25 =
- 2 6/25 <===

Answer 2

Answer:

$-2\frac{6}{25}$

Step-by-step explanation:

If the total weight change was $-11 \frac{1}{5}lb$ in 5 months, then the average would be the quotient between these two quantities, that is

$-11 \frac{1}{5}lb \div 5$

However, we need to transform the mixed number into a fraction. We do that by multiplying -11 by 5 and summing the reminder of 1, so the expression would be

$-\frac{56}{5}lb \div 5$

Now,we divide

$-\frac{56}{5}lb \times \frac{1}{5}=-\frac{56}{25}=-2\frac{6}{25}$

Therefore, the average weight change is

$-2\frac{6}{25}$