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2 years ago

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A fish tank, filled with water, is 100cm long,60cm wide and 40cm high. It is tilted resting on a 60cm edge, with the water level

reaching C, the midpoint of AB. Find the depth of water in the fish tank once AB is returned to a horizontal position.

1 answer:

grin007 [14]2 years ago

7 0

20 cm deep since 50 x 60 x 40 = 10 x 60 x 20

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In the figure above, two line segments in the x-y plane form a right triangle with the x-axis. What is the area of the triangle

Juli2301 [7.4K]

A = (1/2) * b * h
The base is 10; the x-value going from 0 to 10.
The perpendicular height is 2; the y-value going from 0 to 2
A = (1/2) * 10 * 2
A = 10 units ^2

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Jackson is conducting an experiment for his Physics class. He attaches a weight to the bottom of a metal spring. He then pulls t

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We have that the spring is going to have a sin or a cos equation. We have that the maximum distance of the spring is 6 inches and it is achieved at t=0. Let's fix this as the positive edge. Until now, we have that the function is of the form:
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by trigonometric identities.

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2 years ago

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Nisha works at a bank. In her till 35% of the notes are £5 notes, 40% are £10 notes and the rest are £20 notes. If all the £20 n

podryga [215]

Answer:

£1290

Step-by-step explanation:

35%+40%= 75%

£600=25% £600÷20=30 25%of till = 30 notes 100%=120 notes

40% of 120 =48notes 48x10=£480

90notes-48notes=42notes

42x£5=£210

£600+£480+£210=£1290

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1 year ago

a square painting has an area of 81x^2-90x-25. A second square painting has an area of 25x^2+30x+9. What is an expression that r

galina1969 [7]

Answer:

The answer in the procedure

Step-by-step explanation:

Let

A1 ------> the area of the first square painting

A2 ----> the area of the second square painting

D -----> the difference of the areas

we have

$A1=81x^{2}-90x-25$

$A2=25x^{2}+30x+9$

case 1) The area of the second square painting is greater than the area of the first square painting

The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting

D=A2-A1

$D=(25x^{2}+30x+9)-(81x^{2}-90x-25)$

$D=(-56x^{2}+120x+34)$

case 2) The area of the first square painting is greater than the area of the second square painting

The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting

D=A1-A2

$D=(81x^{2}-90x-25)-(25x^{2}+30x+9)$

$D=(56x^{2}-120x-34)$

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2 years ago

Simplify this expression 5xy-x^2t+2xy+3x^2t

Dmitry_Shevchenko [17]

Answer:

$\large\boxed{5xy-x^2t+2xy+3x^2t=7xy+2x^2t}$

Step-by-step explanation:

$5xy-x^2t+2xy+3x^2t\\\\combine\ like\ terms\\\\(5xy+2xy)+(-x^2t+3x^2t)\\\\7xy+2x^2t$

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2 years ago

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