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gladu [14]
2 years ago
7

Which point on the number line represents the product (5)(-2)(-1)

Mathematics
2 answers:
d1i1m1o1n [39]2 years ago
6 0
10

We need to mutiply all the numbers.
5*-2 = -10
-10*-1 = 10
galben [10]2 years ago
3 0
Point +10.

(-2)*(-1) gives +2 (a negative number multiplied for another negative gives a positive number).

2*5 = +10
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Will mark BRAINIEST. Solve this.
Brums [2.3K]

Answer:

3x+7=10x+17

Step-by-step explanation:

1.9

10x

27x

3 0
2 years ago
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Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:
Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. \lim_{n \to \infty} a_n =A it must hold that for any small \epsilon>0, there must exist n_0\in \mathbb{N} so that starting from that term of the series all of the following terms satisfy that  |a_n-A|n_0 .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with a_n=1 , the other is constant with a_n=3 , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}

If we  denote the first series as b_n=1, we will have that \lim_{k \to \infty} b_k=1.

The second series is denoted as c_k=2^k and we have that \lim_{k \to \infty} c_k=+\infty.

The third sub-series d_k=3 is a constant series and it holds that \lim_{k \to \infty} d_k=3.

Since those limits of sub-series are different, we can never find such n_0\\ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose \epsilon =1, all those terms associated with the third sub-series will be out of this interval (A-1, A+1)=(0, 2).

Therefore, the observed series diverges.

5 0
2 years ago
A homemade lip balm consists of coconut oil and beeswax. Coconut oil costs $0.50 per ounce and beeswax costs $2.00 per ounce. If
Alika [10]

Let

a--------> the total cost in dollars of 6 ounces of coconut oil

b--------> the total cost in dollars of 5 ounces of beeswax

we know that

a=0.50 \frac{\$}{ounce}*6=\$3

b=2.00 \frac{\$}{ounce}*5=\$10

therefore

<u>the answer is</u>

the total cost in dollars of 6 ounces of coconut oil is a=\$3

the total cost in dollars of 5 ounces ofbeeswax is b=\$10

7 0
2 years ago
Read 2 more answers
Consider this equation: -2x - 4 + 5x = 8 Generate a plan to solve for the cariable. Describe the steps that will be used.
nordsb [41]
We are given the function –2x – 4 + 5x = 8 and is asked in the problem to solve for the variable x in the function. In this case, we can first group the like terms and put them in their corresponding sides:

-2x + 5x =8+4
Then, do the necessary operations.

3x = 12
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8 0
2 years ago
4. Suppose that Peculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply thr
Viktor [21]

Answer:

Peculiar purples would be more abundant

Step-by-step explanation:

Given that eculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply through a mechanism in which each single  bacterial cell splits into four. Time taken for one split is 12 m for I one and 10 minutes for 2nd

The function representing would be

i) P=P_0 (4)^{t/12} for I bacteria where t is no of minutes from start.

ii) P=P_0 (4)^{t/10} for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

a) Here P0 =3, time t = 60 minutes.

i) I bacteria P = 3(4)^{5} =3072

ii) II bacteria P = 3(4)^{4} =768

b) Since II is multiplying more we find that I type will be more abundant.

The difference in two hours would be

3(4)^{10}- 3(4)^{8} =2949120

c) i) P=P_0 (4)^{t/12} for I bacteria where t is no of minutes from start.

ii) P=P_0 (4)^{t/10} for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

d) At time 36 minutes we have t = 36

Peculiar purples would be

i) P=3 (4)^{36/12}=192

The rate may not be constant for a longer time.  Hence this may not be accurate.

e) when splits into 2, we get

P=P_o (2^t) where P0 is initial and t = interval of time

7 0
2 years ago
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