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2 years ago

A playground measures 300 m × 170 m.Find the cost of planting grass on this at the rate of Rs 80 per hectare.

Mathematics

1 answer:

Ierofanga [76]2 years ago

7 0

<h2><u>Answer</u> :-</h2>

To find the cost of planting grass , we have to find area of the field.

Area of field = Length × Breadth

${= 300×170}$

${=51000 sq. m}$

Now convert into hectare.

1 hectare = 10000m sq.

51000 / 10000

So area field = 5.1 hectare sq.

Now cost = 5.1 x 0.80 p

${= 0.408 p}$

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What values of b satisfy 3(2b + 3)2 = 36?

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What values of b satisfy 3(2b+3)^2 = 36

we have
3(2b+3)^2 = 36
Divide both sides by 3
(2b+3)^2 = 12
take the square root of both sides
( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3

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the answer is
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2 years ago

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Marginal cost At a certain factory the marginal cost is 3(q-4)^2 dollars per unit when the level of production is q units.

viktelen [127]

Answer:

a.) C(q) = -(1/4)*q^3 + 3q^2 - 12q + OH b.) $170

Step-by-step explanation:

(a) Marginal cost is defined as the decrease or increase in total production cost if output is increased by one more unit. Mathematically:

Marginal cost (MC) = change in total cost/change in quantity

Therefore, to derive the equation for total production cost, we need to integrate the equation of marginal cost with respect to quantity. Thus:

Total cost (C) = Integral [3(q-4)^2] dq = -(1/4)*(q-4)^3 + k

where k is a constant.

The overhead (OH) = C(0) = -(1/4)*(0-4)^3 + k = -16 + k

C(q) = -(1/4)*(q^3 - 12q^2 + 48q - 64) + k = -(1/4)*q^3 + 3q^2 - 12q -16 + k

Thus:

C(q) = -(1/4)*q^3 + 3q^2 - 12q + OH

(b) C(14) = -(1/4)*14^3 + 3*14^2 - 12*14 + 436 = -686 + 588 - 168 + 436 = $170

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2 years ago

The blood platelet counts of a group of women have a bell-shaped distribution with a mean of 247.9 and a standard deviation of

labwork [276]

Answer:

A) Approximate percentage of women with platelet counts within 2 standard deviations of the mean, or between 118.5 and 377.3 = 95%

B) approximate percentage of women with platelet counts between 53.8 and 442.0 = 99.7%

Step-by-step explanation:

We are given;

mean;μ = 247.9

standard deviation;σ = 64.7

A) We want to find the approximate percentage of women with platelet counts within 2 standard deviations of the mean, or between 118.5 and 377.3.

Now, from the image attached, we can see that from the empirical curve, the probability of 1 standard deviation from the mean is (34% + 34%) = 68 %.

While probability of 2 standard deviations from the mean is (13.5% + 34% + 34% + 13.5%) = 95%

Thus, approximate percentage of women with platelet counts within 2 standard deviations of the mean, or between 118.5 and 377.3 = 95%

B) Now, we want to find the approximate percentage of women with platelet counts between 53.8 and 442.0.

53.8 and 442.0 represents 3 standard deviations from the mean.

Let's confirm that.

Since mean;μ = 247.9

standard deviation;σ = 64.7 ;

μ = 247.9

σ = 64.7

μ + 3σ = 247.9 + 3(64.7) = 442

Also;

μ - 3σ = 247.9 - 3(64.7) = 53.8

Again from the empirical curve attached, we cans that at 3 standard deviations from the mean, we have a percentage probability of;

(2.35% + 13.5% + 34% + 34% + 13.5% + 2.35%) = 99.7%

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2 years ago

A playground measures 300 m × 170 m.Find the cost of planting grass on this at the rate of Rs 80 per hectare.​

A playground measures 300 m × 170 m.Find the cost of planting grass on this at the rate of Rs 80 per hectare.