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Shalnov [3]
1 year ago
10

Hannah mixed 6.83 lb of pretzels with 3.57 lb of popcorn. After filling up 6 bags that were the same size with the mixture, she

had 0.35 lb left. What was the weight of each bag cant figur it out 5th grade math
Mathematics
1 answer:
liubo4ka [24]1 year ago
8 0

Answer:

1.675 lb

Step-by-step explanation:

Given that Hannah mixed 6.83 lb of pretzels with 3.57 lb of popcorn.

So, after mixing, the total amount of mixture is

6.83 lb + 3.57 lb = 10.40 lb.

After filling up 6 bags that were the same size with the mixture, she had 0.35 lb left, so 0.35 lb of the mixture is not in the bag.

So,he total amount of mixture in 6 bags = 10.40 lb - 0.35 lb=10.05 lb, which is the weight of 6 bags.

The weight of one bag =\frac {10.05}{6} lb

=1.675 lb

As all the bags are of the same size, so the weight of all the bags are same,

Hence, the weight of each bag is 1.675 lb.

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A cement bridge post is 24 inches square and 15 feet 9 inches in length. If the cement weighs 145 pounds per cubic foot, how muc
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Answer:

The answer is option (C), One cement bridge post weighs 9,135 pounds

Step-by-step explanation:

Step 1: Get the total volume of a cement bridge post

The cement bridge post is in the shape of a cuboid, therefor the volume of the cement bridge post can be expressed as;

Volume of cement bridge post=Base area×Length

where;

Base area=(24^2) inches square

1 foot=12 inches

Convert 24 inches to foot=24/12=2^2=4 feet²

Length=15 feet and 9 inches

1 foot=12 inches

Convert 9 inches to foot=9/12=0.75 feet

Total length=(15+0.75)=15.75 feet

replacing;

Volume of cement bridge post=(4×15.75)=63 cubic feet

Volume of cement bridge post=63 cubic feet

Step 2: Get the total weight of the cement bridge post

Total weight of the cement bridge post=Weight per cubic foot×total volume of the cement bridge post

where;

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Total volume of the cement bridge post=63 cubic feet

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Total weight of the cement bridge post=(145×63)=9,135 pounds

One cement bridge post weighs 9,135 pounds

8 0
1 year ago
Mr. Smith had 33 dozen cans. He sold 340 of them at 15$ each. He sold the remaining cans at a discount of 20% each. How much mon
iren2701 [21]

Answer:

Mr. Smith collects $5748 from selling the can.

Step-by-step explanation:

Given total number of cans = 33\times12=396

Selling price of one can = $15.

\therefore \textrm{Selling price of 340 cans} = \textrm {selling price of one can} \times \textrm {number of cans}=15\times340=\$5100

Now remaining number of cans = total number of cans - sold number of cans =396-340=54

For remaining number of cans he gives a discount of 20% each,

∴ Selling price of one can = 15-\frac{15\times20}{100}=15-3=12

∴ Selling price of 54 cans = \textrm{selling price of one can} \times \textrm{number of cans}=12\times54=\$648

So total money he earns =  \$5100+\$648= \$5748.

Thus Mr. Smith earns $5748 by selling the cans.

3 0
2 years ago
The original cost of an item is $64, but you have to pay $78.08. What is the markup of the item (as a percent)?
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Answer:

Step-by-step explanation:

The answer is 22 percent.

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