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arlik [135]
2 years ago
11

Write the expression that shows "3 times the sixth power of 10"

Mathematics
1 answer:
Fantom [35]2 years ago
3 0
3 x 10^6. It looks funny on here but the exponent of 6 goes with 10.
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Jake scored 17 out of 25 points on a math quiz. He then scored 16 out of 20 points on a spelling quiz. On which quiz did Jake sc
Nikolay [14]

Answer:

Jake scored more on the spelling quiz. 80% is more than 68% so therefore he scored more on the quiz. To find 80% and 68%, you can use a percent of proportion or divide and multiply by 100.

Step-by-step explanation:

To find the percent of a score, you divide.

17/25 (division) = 0.68

0.68 is a decimal so to make it a percent you multiply by 100 = 68%

Or you can do it with fractions:

17/25 = ?/100: 68

16/20 = 0.8

Again, 0.8 times 100 = 80%

Or you can do it with fractions:

16/20 = ?/100: 80

He scored more on the spelling quiz, I hope this helps (justification on the answer).

7 0
1 year ago
Charlotte’s weekly paycheck is based on the number of hours worked during the week and on the weekend. If she works 13 hours dur
Gelneren [198K]
I am setting the week hourly rate to x, and the weekend to y.  Here is how the equation is set up:

13x + 14y = $250.90
15x + 8y = $204.70

This is a system of equations, and we can solve it by multiplying the top equation by 4, and the bottom equation by -7.  Now it equals:

52x + 56y = $1003.60
-105x - 56y = -$1432.90

Now we add these two equations together to get:

-53x = -$429.30 --> 53x = $429.30 --> (divide both sides by 53) x = 8.10.  This is how much she makes per hour on a week day.

Now we can plug in our answer for x to find y.  I am going to use the first equation, but you could use either.

$105.30 + 14y = $250.90.  Subtract $105.30 from both sides --> 14y = $145.60 divide by 14 --> y = $10.40

Now we know that she makes $8.10 per hour on the week days, and $10.40 per hour on the weekends.  Subtracting 8.1 from 10.4, we figure out that she makes $2.30 more per hour on the weekends than week days.
7 0
2 years ago
Read 2 more answers
Is 976 -522 more or less than 400? Explain how you can tell without actually subtracting.
liq [111]
You can round 976 to 1000 and 522 to 500. So it would be
1000 - 500 = 500. The answer you would get after subtracting 976-522 would be more than 400 if you round it.
3 0
2 years ago
Read 2 more answers
The average starting salary for graduates at a university is $25,000 with a standard deviation of $4,000. if a histogram of the
kirill115 [55]
The empirical rule says 68% of the distribution should fall within one standard deviation of the mean, so you should expect salaries between \$25000-\$4000=\$21000 and \$25000+\$4000=\$29000
3 0
2 years ago
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
2 years ago
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