Use the law of cosines:
We have:
substitute:
A local amusement park has 30 rides that park visitors can go on. The following table shows the relative frequency distribution
2 answers:
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Two figures are similar if one is the scaled version of the other.
This is always the case for circles, because their geometry is fixed, and you can't modify it in anyway, otherwise it wouldn't be a circle anymore.
To be more precise, you only need two steps to prove that every two circles are similar:
- Translate one of the two circles so that they have the same center
- Scale the inner circle (for example) unit it has the same radius of the outer one. You can obviously shrink the outer one as well
Now the two circles have the same center and the same radius, and thus they are the same. We just proved that any two circles can be reduced to be the same circle using only translations and scaling, which generate similar shapes.
Recapping, we have:
- Start with circle X and radius r
- Translate it so that it has the same center as circle Y. This new circle, say X', is similar to the first one, because you only translated it.
- Scale the radius of circle X' until it becomes
. This new circle, say X'', is similar to X' because you only scaled it
So, we passed from X to X' to X'', and they are all similar to each other, and in the end we have X''=Y, which ends the proof.
Answer:
Width of the uniform path that surrounds the piece of land = 3 m
Step-by-step explanation:
Let the width of the path that surrounds the piece of land be x.
The situation described is sketched in the attached image to this solution.
The dimension of the Length of the piece of land including the uniform path that surrounds it = (40 + 2x) m
The Breadth of the piece of land including the uniform path that surrounds it = (25 + 2x) m
The area of the piece of land including the uniform path that surrounds it
= (Area of the piece of land) + (Area of the uniform path that surrounds it)
Area of the piece of land = Length × Breadth = 40 × 25 = 1000 m²
Area of the uniform path that surrounds it = 426 m² (Given in the question)
The area of the piece of land including the uniform path that surrounds it = 1000 + 426 = 1426 m²
But the area of the piece of land including the uniform path that surrounds it is also
= (Length of the piece of land including the uniform path that surrounds it) × (Breadth of the piece of land including the uniform path that surrounds it
= (40 + 2x) + (25 + 2x)
= 1000 + 80x + 50x + 4x²
= (4x² + 130x + 1000) m²
Equation these 2 areas
4x² + 130x + 1000 = 1426
4x² + 130x - 426 = 0
Solving the quadratic equation
x = 3 or -35.5
Since the width cannot be negative,
x = 3 m
Hope this Helps!!!
