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Vadim26 [7]
2 years ago
6

Find the value of 58-9x

Mathematics
1 answer:
Yuri [45]2 years ago
5 0
You cannot have an answer to this because it is not an equation
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T-shirts and More Print Shop will print any image on a mouse pad for a cost of $2 per mouse pad and a one-time charge of $12 to
SpyIntel [72]

Answer: 275

Step-by-step explanation:

7 0
2 years ago
Zach uses his car for business and must keep accurate driving records so that his company will reimburse him for car expenses. W
Phoenix [80]
His end mileage minus his starting mileage will give us the total number of miles he traveled.  28017-26645=1372 miles traveled.
We can divide that by his average mpg to figure out how many gallons of gas he bought:
1372/48 = 28.583 gallons.
Now divide the amount he paid by this to get the price per gallon:
62.28/28.583 = $2.179 per gallon of gas.
7 0
2 years ago
Sally is hosting an Internet auction to sell n widgets. She receives m bids, each of the form "I want ki widgets for di dollars,
daser333 [38]

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

5 0
2 years ago
The amount of time required to reach a customer service representative has a huge impact on customer satisfaction. Below is the
Vika [28.1K]

Answer:

The value of the test statistic is t=1.12.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that the mean amount of time required to reach a customer service representative significantly differs between the two hotels.

Then, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0

The sample 1, of size n1=20 has a mean of 2.65 and a standard deviation of √2.952=1.72.

The sample 2, of size n2=20 has a mean of 2.01 and a standard deviation of √2.952=1.89.

The difference between sample means is Md=0.64.

M_d=M_1-M_2=2.65-2.01=0.64

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{1.72^2+1.89^2}{20}}\\\\\\s_{M_d}=\sqrt{\dfrac{6.531}{20}}=\sqrt{0.327}=0.571

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.64-0}{0.571}=\dfrac{0.64}{0.571}=1.12

5 0
2 years ago
Part A: During what interval(s) of the domain is the water balloon's height increasing?
Advocard [28]

Answer:

The answer is below

Step-by-step explanation:

The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds: A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet. Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds.

Answer:

Part A: During what interval(s) of the domain is the water balloon's height increasing?

Between 0 and 2 seconds, the height of the balloon increases from 60 feet to 75 feet

Part B: During what interval(s) of the domain is the water balloon's height staying the same?

Between 2 and 4 seconds, the height remains the same at 75 feet. Also from 10 seconds the height of the balloon is at 0 feet

Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest?

Between 4 and 6 seconds, the height of the balloon decreases from 75 feet to 40 feet (i.e. -17.5 ft/s)

Between 6 and 8 seconds, the height of the balloon decreases from 40 feet to 20 feet (i.e. -10 ft/s)

Between 8 and 10 seconds, the height of the balloon decreases from 20 feet to 0 feet (i.e. -10 ft/s)

Hence it decreases fastest from 4 to 6 seconds

Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds

From 10 seconds, the balloon is at the ground, so it remains at the ground (0 feet) even at 16 seconds

6 0
2 years ago
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