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2 years ago

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The price of a movie ticket in a given year can be modeled by the regression equation y = 6.94(1.02x), where y is the ticket pri

ce and x is the year. To the nearest cent, which is the best prediction of the price of a ticket in year 25? (Year 1 = 2007)

2 answers:

topjm [15]2 years ago

5 0

Answer:

11.38.

Step-by-step explanation:

Given :The price of a movie ticket in a given year can be modeled by the regression equation $y = 6.94(1.02^x)$ , where y is the ticket price and x is the year.

To Find: . To the nearest cent, which is the best prediction of the price of a ticket in year 25?

Solution:

$y = 6.94(1.02^x)$

Where y is the ticket price and x is the year.

Now we are supposed to find which is the best prediction of the price of a ticket in year 25

Substitute x = 25 in the given equation.

$y = 6.94(1.02^{25})$

$y =11.38580$

Thus the best prediction of the price of a ticket in year 25 is 11.38.

Whitepunk [10]2 years ago

4 0

I would say that the price would be 176.97.

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2 years ago

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2 years ago

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2 years ago

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maksim [4K]

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$\displaystyle\sum_{n\ge2}a_nx^n=6\sum_{n\ge2}a_{n-1}x^n-8\sum_{n\ge2}a_{n-2}x^n$

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So the recurrence relation is transformed to

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2 years ago

A dealer paid $10,000 for a boat at an auction. At the dealership, a salesperson sold the boat for 30% more than the auction pri

pickupchik [31]

<span>Given situation:
=> A deadler paid $10 000 for a boat at an auction.
=> At the dealership, a sales person sold the boat for 30% more than the auction price
=> 10 000 dollars + 30%
=> Then the salesperson received a commission of 25% of the difference between the auction price and the dealership price
=> 10 000 + 25%
Let’s find the solution
=> 10 000 x .30 = 3000
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=> then he received a commission
=> 13 000 – 3 000 = 10 000
=> 10 000 x .25
=> 2500 , his commission </span>

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2 years ago