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gtnhenbr [62]
2 years ago
7

What is the decibel level of the sound of a ticking clock with intensity 10−9 watts per square inch? Use a logarithmic model to

solve.
Mathematics
2 answers:
In-s [12.5K]2 years ago
7 0

Answer:

β = (-0.19 dB).

Step-by-step explanation:

The formula which is used to calculate the decibel level of a sound is given by :

\beta=10\log (\dfrac{I}{I_o})

I is intensity of the sound of a ticking clock

I_o=10^{-12}\ watts per square meter

Since, 1\ \text{inch}^2=\dfrac{1}{1550}\ \text{m}^2

The intensity of a monster truck is converted into per square meter as follows:  

10^{-9}\ {W/in^2}=   \dfrac{10^{-9}}{1550}\ W/m^2\\\\10^{-9}\ {W/in^2}=6.45\times 10^{-13}\ W/m^2

So, Decibal level is :

\beta=10\log (\dfrac{6.45\times 10^{-13}}{10^{-12}})\\\\\beta =-0.19\ dB

So, the decibel level of the sound of a ticking clock is (-0.19 dB).

nikklg [1K]2 years ago
4 0

Answer:

30dB

Step-by-step explanation:

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Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

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c

The critical value is  Z_{\frac{\alpha }{2} } =  1.96

d

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Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

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Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

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        \alpha  =  0.05

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Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

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The  margin of error is  

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=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

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Answer:

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Step-by-step explanation:

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In the complex plane the real numbers are located in the horizontal axis, increasing to the right. The positives real numbers are at the right of the origin and the negatives to the left.

The complex numbers are located in the vertical axis, with the positives over the origin and the negatives below the origin.

This complex number 5-2i is the sum of a real part (5) and a imaginary part (-2i), so the point will be 5 units rigth on the horizontal axis (for the real part) and 2 units down in the vertical axis (for the imaginary part).

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