Question

What is the decibel level of the sound of a ticking clock with intensity 10−9 watts per square inch? Use a logarithmic model to solve.

Answer 1

Answer:

β = (-0.19 dB).

Step-by-step explanation:

The formula which is used to calculate the decibel level of a sound is given by :

$\beta=10\log (\dfrac{I}{I_o})$

I is intensity of the sound of a ticking clock

$I_o=10^{-12}$ watts per square meter

Since, $1\ \text{inch}^2=\dfrac{1}{1550}\ \text{m}^2$

The intensity of a monster truck is converted into per square meter as follows:  

$10^{-9}\ {W/in^2}= \dfrac{10^{-9}}{1550}\ W/m^2\\\\10^{-9}\ {W/in^2}=6.45\times 10^{-13}\ W/m^2$

So, Decibal level is :

$\beta=10\log (\dfrac{6.45\times 10^{-13}}{10^{-12}})\\\\\beta =-0.19\ dB$

So, the decibel level of the sound of a ticking clock is (-0.19 dB).

Answer 2

Answer:

30dB

Step-by-step explanation: