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Allushta [10]
2 years ago
13

Let d(t) be the total number of miles Joanna has cycled, and let t represent the number of hours after stopping for a break duri

ng her ride.
d(t)=12t+20

So,_______ d(4) = . This means that after _____________, Joanna __________.
Mathematics
2 answers:
Alexandra [31]2 years ago
7 0

Answer:

68

Step-by-step explanation:

Naddik [55]2 years ago
5 0

Answer:

d(4)=?

where

d= distance

t= hours

In this Linear function given by the law d(t) = 12t +20 and the graph below. To find the d(4), means to find out how many miles she cycled in the instant 4 hours.

By this function, after a break , the instant t=0, she had already cycled 20 miles.

Let's calculate

d(4) = 12(4) +20

d(4) =48+20

d(4)= 68 miles

Step-by-step explanation:

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Jack bought seven tickets for a movie he paid seven dollars for each adult ticket and four dollars for each child ticket jack sp
Alja [10]

7x = 40

7x + 4y = 40

The first equation represents that in total, the 7 tickets whether they are for adults or children costs $40.

The second equation represents that x = adult and y = children tickets both add up to equal $40.

7 0
2 years ago
Mary deposits $550 in a savings account at 3% simple annual interest. The
kupik [55]

Answer:

Domain: t \geq 0

Range: v \geq 550

Step-by-step explanation:

Given

v = 550 + 16.5t

Required

Determine the domain and the range

Solving for domain:

From the question, we understand that t represent years.

Because years can't be negative;

Then, we can conclude that the domain, t is:

t \geq 0

Solving for Range:

We solved domain to be t \geq 0

This implies that the minimum value of t is t = 0 and the maximum is infinity

Substitute 0 for t in v = 550 + 16.5t

v = 550 + 16.5(0)

v = 550 + 0

v = 550

Hence;

The range is v \geq 550

6 0
2 years ago
In a West Texas school district the school year began on August 1 and lasted until May 31. On August 1 a Soft Drink company inst
WINSTONCH [101]

Answer:

$95.78

Step-by-step explanation:

f(t) = 300t / (2t² + 8)

t = 0 corresponds to the beginning of August.  t = 1 corresponds to the end of August.  t = 2 corresponds to the end of September.  So on and so forth.  So the second semester is from t = 5 to t = 10.

$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt

$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt

$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt

$T₂ = 75 ln(t² + 4) |₅¹⁰

$T₂ = 75 ln(104) − 75 ln(29)

$T₂ ≈ 95.78

3 0
2 years ago
Using only the values given in the table for the function f(x) = –x3 + 4x + 3, what is the largest interval of x-values where th
nikklg [1K]
I assume you mean -x^3 + 4x + 3 
so what you need is 4x + 3 > x^3
the only whole number it could be is 2 because 2x2x2 +3 > 2x2x2

4 0
2 years ago
Read 2 more answers
An online furniture store sells chairs for $200 each and tables for $600 each. Every day, the store can ship a maximum of 32 pie
wolverine [178]

Answer:

If the minimum 13 chair were sold , then the minimum number of Table sold is 14

Step-by-step explanation:

Given as :

The cost of each chair = $ 200

The cost of each table = $ 600

The total number of furniture sold per day = 32

The minimum amount of selling per day = $ 12000

Let the total number of chair = C

The total number of table = T

So , according to question

C + T = 32         .......1

200 C + 600 T = 12000         .......2

Solving eq 1 and 2

200 C + 600 T = 12000

200 × ( C + T ) = 32 × 200

I.e 200 C + 200 T = 6400

or, ( 200 C + 600 T ) - ( 200 C + 200 T ) = 12,000 - 6400

Or, 400 T =  5600

∴  T = \frac{5600}{400}

I.e T = 14

Put The value of T in eq 2

So, 200 C + 600 × 14 = 12000

or , 200 C + 8400 = 12,000

Or, 200 C = 12000 - 8400

Or, 200 C = 3600

∴   C = \frac{3600}{200}

I.e C = 18

The number of chair sold is 18

If the number of chair sold is 13 ,

Then the min number of table sold = 200 × 18 + 600 T = 12000

i.e 600 T = 12000 - 3600

or, 600 T = 8400

∴   T = \frac{8400}{600}

I.e T = 14

Hence if the minimum 13 chair were sold , then the minimum number of Table sold is 14 . Answer

5 0
2 years ago
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